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Radioactive decay is a first order rate reaction, so the expression for the rate is: log 10 X 0 /X = kt/2.30 where X 0 is the quantity of radioactive substance at zero time (when the counting process starts) and X is the quantity remaining after time t .

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PROBLEM \(\PageIndex{10}\) Technetium-99 is prepared from 98 Mo. Molybdenum-98 combines with a neutron to give molybdenum-99, an unstable isotope that emits a β particle to yield an excited form of technetium-99, represented as 99 Tc *.This excited nucleus relaxes to the ground state, represented as 99 Tc, by emitting a γ ray. The ground state of 99 Tc then emits a β particle.

The mass of a radioactive material decreases as a result of decay twice after each half life. So, after 3 half lives the quantity of the material will be (1 2)3 = 1 8 of the initial amount. Hence, the mass after decay is 80g⋅ 1 8 = 10g. The initial mass of an Iodine isotope was 200g. Determine the Iodine mass after 30 days if the half life of ...

25 Questions Show answers. Q. Which type of nuclear radiation is being emitted here? Q. In the equation, 146 C --> 147 N + 0-1 B, the _______ decay of radioactive carbon-14 results in the creation of a new nitrogen-14 atom. Q. What particle completes this reaction? Q. What element is the ? Q. Which type of nuclear radiation is being emitted here?

Explanation: . This is an exponential decay problem. Therefore, we can use this equation. is the animal population after the 7 years. is the animal population right now. is the decay of the animal population every year. is the time period of the animal populations decay. From the problem we know after the 7 years the animal population will be 80, so

SAL: Let's do a couple more of these exponential decay problems, because a lot of this really is just practice and being very comfortable with the general formula, and I'll write it again. Where the amount of the element that's decaying, that we have at any period in time, is equal to the amount that we started with, times e to the minus kt.