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How To: Given the equation of a function and a point through which its graph passes, write the equation of a line perpendicular to the given line. Find the slope of the function. Determine the negative reciprocal of the slope. Substitute the new slope and the values for x and y from the coordinate pair provided into [latex] ...

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Write the equation of a line perpendicular to y = 3 8 x – 3 and whose y-intercept is (0,12). 5. Write the equation of a line that is perpendicular toy = 4 5 x – 3 that passes through the point (5,-10) Homework 1) The two lines below are not parallel. Explain why a. y - 2x =3

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The equation of a perpendicular line must have a slope that is the negative reciprocal of the original slope. Find the equation of the perpendicular line using the point-slope formula.

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Hence, the equation of a line perpendicular to x axis is x = c. Note : If the line is passing through some other value on x axis, we have to replace "c" by that value. Apart from the equation of a line which is perpendicular to x axis, let us look at some other different forms of equation of straight line.

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The answer is an equation, in slope intercept form, of the line perpendicular to the line entered and passing through the point entered . The coordinates and coefficients may be entered as fractions, integers or decimals.(see examples below).

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Find the equation of a line that is perpendicular to y = -9x + 5 and passes through the point (3,9) 3. Find the slope-intercept form of the equation of a line that is parallel to the graphed line and that passes through the point plotted on the graph. Show Step-by-step Solutions.

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The slope "m 1" of the line perpendicular to (1) is defined as a reciprocal to "m" with negative sign: m 1 = -1/m. Thus we have for the equation of the perpendicular line: y = (B/A)x + c (2) where "c" is to be found. In order to find "c" we have to use the point (a,b).

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Find the Equation of Perpendicular Bisector : Here we are going to see how to find the equation of perpendicular bisector. Find the Equation of Perpendicular Bisector - Example. Question 10 : Find the equation of the perpendicular bisector of the straight line segment joining the points (3,4) and (-1,2) Solution :

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To find the equation of a line you need a point and a slope.; The slope of the tangent line is the value of the derivative at the point of tangency.; The normal line is a line that is perpendicular to the tangent line and passes through the point of tangency.

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To construct a vector that is perpendicular to another given vector, you can use techniques based on the dot-product and cross-product of vectors. The dot-product of the vectors A = (a1, a2, a3) and B = (b1, b2, b3) is equal to the sum of the products of the corresponding components: A∙B = a1*b2 + a2*b2 + a3*b3. If ...