Q:

What are the flywheel torque specifications for a Ford F-150?

A:

Quick Answer

The F-150 line of Ford pickup trucks requires 60 to 62 foot pounds of torque between the flywheel and the engine crankshaft, and either 18, 40 or 42 foot pounds for bolts connecting the clutch's pressure plate to the flywheel. The exact amount of torque needed depends on the size of the engine.

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Full Answer

The Ford F-150 is typically offered in a 4.2 liter V-6, a 4.6 liter V-8 or a 5.4 liter V-8, and was available with manual transmissions until 2008. The 4.2 and 5.4 liter engines require 40 foot pounds of torque between the pressure plate and the flywheel, and 60 foot pounds between the flywheel and crankshaft. The 4.6 liter engine only requires 18 foot pounds between the pressure plate and flywheel, and 62 foot pounds between the flywheel and crankshaft.

Proper torque specifications are important in the operation of any vehicle's engine. Exact measurements can be found by searching make, model and engine online, and can sometimes be found in the owner's manual. It is also important to not guess at how much torque is needed, especially when it involves an engine's moving parts.

Correct torque measurement can be attained by purchasing a torque wrench, available at any auto parts store. Torque wrenches look like typical ratchets used in automotive maintenance, and are available in commonly used one-fourth, three-eighths or one-half inch drives. Many torque wrenches have an analog dial, which can be set by the user to reach the proper torque and avoid overtightening. Some newer wrenches can be adjusted digitally.

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