What Is the Wavelength of the Fundamental Resonant Frequency of a Closed Tube That Is 35 Cm Long?


Quick Answer

The fundamental frequency of a closed tube that is 35 centimetres long is approximately 246.4 Hertz, assuming sound is traveling at 345 metres per second. The formula for obtaining this number is f(1)=nv/4L.

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Full Answer

In this case, the fundamental frequency, or f(1), equals the number of the frequency, n, times the velocity, v, divided by four times the length of the tube. In this problem, n=1 because it is the fundamental, and the length is given as 35 centimetres, or 0.35 meters. The velocity, 345, is an example of a common number, but it may change. Simplifying, the problem becomes f(1)=(1x345)/(4/0.35). Further, it becomes f(1)=345/1.4, which equals around 246.4.

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