How Many Moles of NaOH Are Required to Neutralize 2.4 Mol H2SO4?
It takes 4.8 moles of sodium hydroxide (NaOH) to neutralize 2.4 moles of sulfuric acid (H2SO4). The process for solving the correct number of moles of NaOH involves the use of the mole ratio between NaOH and H2SO4.
The reaction between an acid, such as H2SO4, and a base, such as NaOH, is known as a neutralization reaction, which produces a salt compound and water. The balanced reaction between NaOH and H2SO4 can be represented by the chemical equation 2 NaOH + H2SO4 → Na2SO4 + 2 H2O.
Based on the equation, the mole ratio between NaOH and H2SO4 is 2:1, meaning that it takes twice the amount of NaOH as H2SO4, for the base to completely neutralize the acid and produce sodium sulfate and water. Hence, the number of moles of NaOH needed to burn 2.4 moles of H2SO4 is calculated by multiplying 2.4 moles by 2.