The chemical reaction between aluminum and bromine is an exothermic one that produces aluminum bromide. The equation of the chemical reaction is 2 Al + 3 Br2 ? 2 AlBr3. It indicates that two molecules of aluminum combine with three molecules of bromine to produce two molecules of aluminum bromide.
Aluminum is a metal, and bromine is a halogen liquid at room temperature. When the two chemical substances combine, energy in the form of light and heat is produced. The total energy produced when one molecule of aluminum bromide is formed is 526 kilojoules per mole. The resultant aluminum bromide is a salt in its native state but a gas at high temperatures.