wild rose

Wild Rose, Wisconsin

Wild Rose is a village in Waushara County, Wisconsin, United States. The population was 765 at the 2000 census.


Wild Rose is located at (44.177054, -89.246242).

According to the United States Census Bureau, the village has a total area of 1.3 square miles (3.5 km²), of which, 1.3 square miles (3.4 km²) of it is land and 0.04 square miles (0.1 km²) of it (1.49%) is water.


As of the census of 2000, there were 765 people, 312 households, and 186 families residing in the village. The population density was 580.1 people per square mile (223.8/km²). There were 339 housing units at an average density of 257.0/sq mi (99.2/km²). The racial makeup of the village was 97.25% White, 0.78% African American, 0.13% Native American, 0.26% Asian, 0.92% from other races, and 0.65% from two or more races. Hispanic or Latino of any race were 2.22% of the population.

There were 312 households out of which 29.5% had children under the age of 18 living with them, 43.9% were married couples living together, 11.2% had a female householder with no husband present, and 40.1% were non-families. 36.9% of all households were made up of individuals and 19.6% had someone living alone who was 65 years of age or older. The average household size was 2.26 and the average family size was 2.97.

In the village the population was spread out with 23.5% under the age of 18, 5.8% from 18 to 24, 22.7% from 25 to 44, 21.3% from 45 to 64, and 26.7% who were 65 years of age or older. The median age was 43 years. For every 100 females there were 83.5 males. For every 100 females age 18 and over, there were 76.7 males.

The median income for a household in the village was $30,655, and the median income for a family was $37,361. Males had a median income of $32,188 versus $20,438 for females. The per capita income for the village was $18,887. About 4.2% of families and 6.6% of the population were below the poverty line, including 4.1% of those under age 18 and 12.8% of those age 65 or over.


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