Roff, Oklahoma

Roff is a town in Pontotoc County, Oklahoma, United States. The population was 734 at the 2000 census.


Roff is located at (34.626746, -96.841478). According to the United States Census Bureau, the town has a total area of 0.9 square miles (2.4 km²), of which, 0.9 square miles (2.4 km²) of it is land and 1.06% is water.


As of the census of 2000, there were 734 people, 287 households, and 206 families residing in the town. The population density was 782.8 people per square mile (301.5/km²). There were 328 housing units at an average density of 349.8/sq mi (134.7/km²). The racial makeup of the town was 86.10% White, 0.14% African American, 10.35% Native American, 0.14% from other races, and 3.27% from two or more races. Hispanic or Latino of any race were 0.54% of the population.

There were 287 households out of which 35.9% had children under the age of 18 living with them, 55.1% were married couples living together, 11.5% had a female householder with no husband present, and 28.2% were non-families. 26.5% of all households were made up of individuals and 15.7% had someone living alone who was 65 years of age or older. The average household size was 2.56 and the average family size was 3.08.

In the town the population was spread out with 27.4% under the age of 18, 9.3% from 18 to 24, 27.5% from 25 to 44, 19.9% from 45 to 64, and 15.9% who were 65 years of age or older. The median age was 36 years. For every 100 females there were 97.3 males. For every 100 females age 18 and over, there were 90.4 males.

The median income for a household in the town was $21,576, and the median income for a family was $30,156. Males had a median income of $30,125 versus $15,250 for females. The per capita income for the town was $12,157. About 19.0% of families and 18.8% of the population were below the poverty line, including 26.3% of those under age 18 and 7.9% of those age 65 or over.


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