Definitions
Nearby Words

# kinematics

[kin-uh-mat-iks, kahy-nuh-]
kinematics: see dynamics.
Kinematics (Greek κινειν, kinein, to move) is a branch of classical mechanics which describes the motion of objects without consideration of the circumstances leading to the motion. The other branch is dynamics, which studies the relationship between the motion of objects and its causes. Kinematics is not to be confused with kinetics, an obsolete term equivalent to dynamics as used in modern day physics; this term is no longer in active use. (See dynamics for details.)

An example is the prediction of centripetal force in uniform circular motion, regardless of whether the circular path is due to gravitational attraction, a banked curve on a highway, or an attached string. In contrast, kinetics is concerned with the forces and interactions that produce or affect the motion. The simplest application of kinematics is to point particle motion (translational kinematics or linear kinematics). The description of rotation (rotational kinematics or angular kinematics) is more complicated. The state of a generic rigid body may be described by combining both translational and rotational kinematics (rigid-body kinematics). A more complicated case is the kinematics of a system of rigid bodies, possibly linked together by mechanical joints. The kinematic description of fluid flow is even more complicated, and not generally thought of in the context of kinematics.

## Linear motion

Linear or translational kinematics is the description of the motion in space of a point along a line, also known as trajectory or path. This path can be either straight (rectilinear) or curved (curvilinear). There are three basic concepts that are required for understanding linear motion:

Displacement (denoted by r below, but in some cases s or x) is the shortest distance between two points: the origin and the displaced point. The origin is (0,0) on a coordinate system that is defined by the observer. Because displacement has both magnitude (length) and direction, it is a vector whose initial point is the origin and terminal point is the displaced point.

Velocity (denoted by υ below) is the rate of change in displacement with respect to time; that is the displacement of a point changes with time. Velocity is also a vector. For a constant velocity, every unit of time adds the length of the velocity vector (in the same direction) to the displacement of the moving point. Instantaneous velocity (the velocity at an instant of time) is defined as

$boldsymbol v = frac \left\{d boldsymbol r\right\}\left\{d t\right\} ,$
where dr is an infinitesimally small displacement and dt is an infinitesimally small length of time. Because dr is necessarily the distance between two infinitesimally spaced points along the trajectory of the point, it is the same as an increment in arc length along the path of the point, customarily denoted ds. Average velocity (velocity over a length of time) is defined as $boldsymbol v = frac \left\{Delta boldsymbol s\right\}\left\{Delta t\right\}$, where Δs is the change in displacement and Δt is the interval of time over which displacement changes.

Acceleration (denoted by a below) is the rate of change in velocity with respect to time. Acceleration is also a vector. As with velocity if acceleration is constant, for every unit of time the length of the acceleration vector (in the same direction) is added to the velocity. If the change in velocity (a vector) is known, the acceleration is parallel to it. Instantaneous acceleration (the acceleration at an instant of time) is defined as:

$boldsymbol a = frac \left\{d boldsymbol v\right\}\left\{d t\right\} ,$
where d υ is an infinitesimally small change in velocity and dt is an infinitesimally small length of time. Average acceleration (acceleration over a length of time) is defined as:
$boldsymbol a = frac \left\{Delta boldsymbol v\right\}\left\{Delta t\right\} ,$
where Δ υ is the change in velocity and Δt is the interval of time over which velocity changes.

### Integral relations

The above definitions can be inverted by integration to find:
$boldsymbol\left\{v\right\}\left(t\right) =boldsymbol\left\{v\right\}_0+ int_0^t dt\text{'} boldsymbol\left\{a\right\} \left(t\text{'}\right)$
$boldsymbol\left\{r\right\}\left(t\right) =boldsymbol\left\{r\right\}_0+ int_0^t dt\text{'} boldsymbol\left\{v\right\} \left(t\text{'}\right)$
$=boldsymbol\left\{r\right\}_0+boldsymbol\left\{v\right\}_0 t + int_0^t dt\text{'} int_0^\left\{t\text{'}\right\} dt$ boldsymbol{a} (t)
$=boldsymbol\left\{r\right\}_0+boldsymbol\left\{v\right\}_0 t + int_0^t dt\text{'} left\left(t-t\text{'}right\right) boldsymbol\left\{a\right\} \left(t\text{'}\right) ,$
where the double integration is reduced to one integration by interchanging the order of integration, and subscript 0 signifies evaluation at t = 0 (initial values).

### Constant acceleration

When acceleration is constant both in direction and in magnitude, the point is said to be undergoing uniformly accelerated motion. In this case, the above equations can be simplified:Eq. (1)
$boldsymbol v = int_0^\left\{t\right\} boldsymbol a dt = boldsymbol\left\{ v\right\}_0 + boldsymbol a t$
Those who are familiar with calculus may recognize this as an initial value problem. Because acceleration ( a ) is a constant, integrating it with respect to time (t) gives a change in velocity. Adding this to the initial velocity ( υ0) gives the final velocity ( υ ).Eq. (2)
$boldsymbol r = int_0^t boldsymbol v dt = int_0^t left\left(boldsymbol v_0 + boldsymbol a t right\right) dt = boldsymbol v_0 t + frac\left\{1\right\}\left\{2\right\} boldsymbol a t^2$
Using the above formula, we can substitute for υ to arrive at this equation, where r is displacement.Eq. (3)
$boldsymbol r = frac\left\{boldsymbol v+ boldsymbol v_0\right\}\left\{2\right\} t$
By using the definition of an average, this equation states that average velocity times time equals displacement. Using Eq. (1) to find υ−υ0 and multiplying by Eq. (3) we find a connection between the final velocity at time t and the displacement at that time:
$boldsymbol \left\{r cdot a\right\} t = left\left(boldsymbol v - boldsymbol \left\{v\right\}_0 right\right)boldsymbol\left\{ cdot\right\} frac\left\{boldsymbol v + boldsymbol \left\{v\right\}_0\right\}\left\{2\right\} t ,$
where the "" denotes a vector dot product. Dividing the t on both sides and carrying out the dot-products:Eq. (4)
$2 boldsymbol\left\{r cdot a\right\} = v^2 - v_0^2 .$
For the case where r is parallel to a resulting in a straight-line motion, the vector r has magnitude equal to the path length s at time t, and this equation becomes:
$v^2= v_0^2 + 2 a s ,$
which can be a useful result when time is not known explicitly. Eq. (5) If the distance travelled and time taken are known for two consecutive time intervals then the average speed in each interval $<\left\{v\right\}_1>$ and $<\left\{v\right\}_2>$, the average time of the two intervals  and the (constant) acceleration are related by:
$< \left\{v\right\}_2 > = <\left\{v\right\}_1> + a$
In particular if the two intervals are of unit time then the acceleration is numerically equal to the difference between the average speeds: $a = < \left\{v\right\}_2 > - <\left\{v\right\}_1>$.

### Relative velocity

To describe the motion of object A with respect to object B, when we know how each is moving with respect to a reference object O, we can use vector algebra. Choose an origin for reference, and let the positions of objects A, B, and O be denoted by rA, rB, and rO. Then the position of A relative to the reference object O is

$boldsymbol\left\{r\right\}_\left\{A/O\right\} = boldsymbol\left\{r\right\}_\left\{A\right\} - boldsymbol\left\{r\right\}_\left\{O\right\} ,!$
Consequently, the position of A relative to B is

$boldsymbol\left\{r\right\}_\left\{A/B\right\} = boldsymbol\left\{r\right\}_A - boldsymbol\left\{r\right\}_B = boldsymbol\left\{r\right\}_A - boldsymbol\left\{r\right\}_O - left\left(boldsymbol\left\{r\right\}_B-boldsymbol\left\{r\right\}_Oright\right) = boldsymbol\left\{r\right\}_\left\{A/O\right\}-boldsymbol\left\{r\right\}_\left\{B/O\right\} .$

The above relative equation states that the motion of A relative to B is equal to the motion of A relative to O minus the motion of B relative to O. It may be easier to visualize this result if the terms are re-arranged:

$boldsymbol\left\{r\right\}_\left\{A/O\right\} = boldsymbol\left\{r\right\}_\left\{A/B\right\} + boldsymbol\left\{r\right\}_\left\{B/O\right\} ,$

or, in words, the motion of A relative to the reference is that of B plus the relative motion of A with respect to B. These relations between displacements become relations between velocities by simple time-differentiation, and a second differentiation makes them apply to accelerations.

For example, let Ann move with velocity $boldsymbol\left\{V\right\}_\left\{A\right\}$ relative to the reference (we drop the O subscript for convenience) and let Bob move with velocity $boldsymbol\left\{V\right\}_\left\{B\right\}$, each velocity given with respect to the ground (point O). To find how fast Ann is moving relative to Bob (we call this velocity $boldsymbol\left\{V\right\}_\left\{A/B\right\}$), the equation above gives:

$boldsymbol\left\{V\right\}_\left\{A\right\} = boldsymbol\left\{V\right\}_\left\{B\right\} + boldsymbol\left\{V\right\}_\left\{A/B\right\} ,! .$

To find $boldsymbol\left\{V\right\}_\left\{A/B\right\}$ we simply rearrange this equation to obtain:

$boldsymbol\left\{V\right\}_\left\{A/B\right\} = boldsymbol\left\{V\right\}_\left\{A\right\} -boldsymbol\left\{V\right\}_\left\{B\right\} ,! .$

At velocities comparable to the speed of light, these equations are not valid. They are replaced by equations derived from Einstein's theory of special relativity.

## Rotational motion

Rotational or angular kinematics is the description of the rotation of an object. The description of rotation requires some method for describing orientation, for example, the Euler angles. In what follows, attention is restricted to simple rotation about an axis of fixed orientation. The z-axis has been chosen for convenience.

Description of rotation then involves these three quantities:

Angular position: The oriented distance from a selected origin on the rotational axis to a point of an object is a vector r (t ) locating the point. The vector r (t ) has some projection (or, equivalently, some component) r$perp$ (t ) on a plane perpendicular to the axis of rotation. Then the angular position of that point is the angle θ from a reference axis (typically the positive x-axis) to the vector r$perp$ (t ) in a known rotation sense (typically given by the right-hand rule).

Angular velocity: The angular velocity ω is the rate at which the angular position θ changes with respect to time t:

$mathbf\left\{omega\right\} = frac \left\{mathrm\left\{d\right\}theta\right\}\left\{mathrm\left\{d\right\}t\right\}$

The angular velocity is represented in Figure 1 by a vector Ω pointing along the axis of rotation with magnitude ω and sense determined by the direction of rotation as given by the right-hand rule.

Angular acceleration: The magnitude of the angular acceleration $alpha$ is the rate at which the angular velocity $omega$ changes with respect to time t:

$mathbf\left\{alpha\right\} = frac \left\{mathrm\left\{d\right\}mathbf\left\{omega\right\}\right\}\left\{mathrm\left\{d\right\}t\right\}$

The equations of translational kinematics can easily be extended to planar rotational kinematics with simple variable exchanges:

$,!theta_f - theta_i = omega_i t + frac\left\{1\right\}\left\{2\right\} alpha t^2 qquad theta_f - theta_i = frac\left\{1\right\}\left\{2\right\} \left(omega_f + omega_i\right)t$
$,!omega_f = omega_i + alpha t qquad alpha = frac\left\{omega_f - omega_i\right\}\left\{t\right\} qquad omega_f^2 = omega_i^2 + 2 alpha \left(theta_f - theta_i\right) .$

Here $,!theta_i$ and $,!theta_f$ are, respectively, the initial and final angular positions, $,!omega_i$ and $,!omega_f$ are, respectively, the initial and final angular velocities, and $,!alpha$ is the constant angular acceleration. Although position in space and velocity in space are both true vectors (in terms of their properties under rotation), as is angular velocity, angle itself is not a true vector.

#### Point object in circular motion

This example deals with a "point" object, by which is meant that complications due to rotation of the body itself about its own center of mass are ignored.

Displacement. An object in circular motion is located at a position r (t ) given by:

$boldsymbol\left\{r\right\} \left(t\right) = R mathbf\left\{u\right\}_R \left(t\right) ,$
where uR is a unit vector pointing outward from the axis of rotation toward the periphery of the circle of motion, located at a radius R from the axis.

Linear velocity. The velocity of the object is then

$boldsymbol\left\{v\right\} \left(t\right) =frac\left\{d\right\}\left\{dt\right\} boldsymbol\left\{r\right\} \left(t\right) = R frac\left\{d\right\}\left\{dt\right\}mathbf\left\{u\right\}_R \left(t\right) .$
The magnitude of the unit vector uR (by definition) is fixed, so its time dependence is entirely due to its rotation with the radius to the object, that is,
$frac\left\{d\right\}\left\{dt\right\}mathbf\left\{u\right\}_R \left(t\right) = boldsymbol\left\{Omega\right\} mathbf\left\{times u\right\}_R = omega \left(t\right) mathbf\left\{ u\right\}_\left\{theta\right\} ,$
where uθ is a unit vector perpendicular to uR pointing in the direction of rotation, ω (t ) is the (possibly time varying) angular rate of rotation, and the symbol × denotes the vector cross product. The velocity is then:
$boldsymbol\left\{v\right\} \left(t\right) = Romega \left(t\right) mathbf\left\{ u\right\}_\left\{theta\right\} .$
The velocity therefore is tangential to the circular orbit of the object, pointing in the direction of rotation, and increasing in time if ω increases in time.

Linear acceleration. In the same manner, the acceleration of the object is defined as:

$boldsymbol\left\{a\right\} \left(t\right) = frac\left\{d\right\}\left\{dt\right\} boldsymbol\left\{v\right\} \left(t\right) = Rfrac\left\{d\right\}\left\{dt\right\}omegamathbf\left\{ u\right\}_\left\{theta\right\}$
$=mathbf\left\{ u\right\}_\left\{theta\right\} Rfrac\left\{d\right\}\left\{dt\right\}omega + Romegafrac\left\{d\right\}\left\{dt\right\}mathbf\left\{ u\right\}_\left\{theta\right\}$
$=mathbf\left\{ u\right\}_\left\{theta\right\} Rfrac\left\{d\right\}\left\{dt\right\}omega + Romega boldsymbol\left\{Omega\right\}mathbf\left\{ times u\right\}_\left\{theta\right\}$
$=mathbf\left\{ u\right\}_\left\{theta\right\} Rfrac\left\{d\right\}\left\{dt\right\}omega - mathbf\left\{ u\right\}_\left\{R\right\}omega^2R$
$=mathbf\left\{a\right\}_\left\{theta\right\} + mathbf\left\{a\right\}_R ,$
which shows a leading term aθ in the acceleration tangential to the orbit related to the angular acceleration of the object (supposing ω to vary in time) and a second term aR directed inward from the object toward the center of rotation, called the centripetal acceleration.

## Coordinate systems

In any given situation, the most useful coordinates may be determined by constraints on the motion, or by the geometrical nature of the force causing or affecting the motion. Thus, to describe the motion of a bead constrained to move along a circular hoop, the most useful coordinate may be its angle on the hoop. Similarly, to describe the motion of a particle acted upon by a central force, the most useful coordinates may be polar coordinates.

### Fixed rectangular coordinates

In this coordinate system, vectors are expressed as an addition of vectors in the x, y, and z direction from a non-rotating origin. Usually i, j, k are unit vectors in the x-, y-, and z-directions.

The position vector, r (or s), the velocity vector, v, and the acceleration vector, a are expressed using rectangular coordinates in the following way:

$boldsymbol\left\{ r\right\} = x hat \left\{mathbf\left\{ i\right\}\right\} + y hat \left\{mathbf\left\{ j\right\}\right\} + z hat \left\{mathbf\left\{ k\right\}\right\} , !$

$boldsymbol\left\{ v\right\} = dot \left\{boldsymbol\left\{ r\right\}\right\} = dot \left\{x\right\} hat \left\{mathbf\left\{ i\right\}\right\} + dot \left\{y\right\} hat \left\{mathbf\left\{ j\right\}\right\} + dot \left\{z\right\} hat \left\{mathbf\left\{ k\right\}\right\} , !$

$boldsymbol\left\{ a\right\} = ddot \left\{boldsymbol\left\{ r\right\}\right\} = ddot \left\{x\right\} hat \left\{mathbf\left\{ i\right\}\right\} + ddot \left\{y\right\} hat \left\{mathbf\left\{ j\right\}\right\} + ddot \left\{z\right\} hat \left\{mathbf\left\{ k\right\}\right\} , !$

Note: $dot \left\{x\right\} = frac\left\{mathrm\left\{d\right\}x\right\}\left\{mathrm\left\{d\right\}t\right\}$ , $ddot \left\{x\right\} = frac\left\{mathrm\left\{d\right\}^2x\right\}\left\{mathrm\left\{d\right\}t^2\right\}$

### Two dimensional rotating reference frame

This coordinate system expresses only planar motion. It is based on three orthogonal unit vectors: the vector i, and the vector j which form a basis for the plane in which the objects we are considering reside, and k about which rotation occurs. Unlike rectangular coordinates, which are measured relative to an origin that is fixed and non-rotating, the origin of these coordinates can rotate and translate - often following a particle on a body that is being studied.

#### Derivatives of unit vectors

The position, velocity, and acceleration vectors of a given point can be expressed using these coordinate systems, but we have to be a bit more careful than we do with fixed frames of reference. Since the frame of reference is rotating, the unit vectors also rotate, and this rotation must be taken into account when taking the derivative of any of these vectors. If the coordinate frame is rotating at angular rate ω in the counterclockwise direction (that is, Ω = ω k using the right hand rule) then the derivatives of the unit vectors are as follows:

$dot\left\{hat \left\{mathbf\left\{ i\right\}\right\}\right\} = omega hat \left\{mathbf\left\{ k\right\}\right\} times hat \left\{mathbf\left\{ i\right\}\right\} = omegahat \left\{mathbf\left\{ j\right\}\right\}$

$dot\left\{hat \left\{mathbf\left\{ j\right\}\right\}\right\} = omega hat \left\{mathbf\left\{ k\right\}\right\}times hat \left\{mathbf\left\{ j\right\}\right\} = - omega hat \left\{mathbf\left\{ i\right\}\right\}$

#### Position, velocity, and acceleration

Given these identities, we can now figure out how to represent the position, velocity, and acceleration vectors of a particle using this reference frame.
##### Position
Position is straightforward:

$boldsymbol\left\{ r\right\} = x hat \left\{mathbf\left\{ i\right\}\right\} + y hat \left\{mathbf\left\{ j\right\}\right\}$

It is just the distance from the origin in the direction of each of the unit vectors.

##### Velocity
Velocity is the time derivative of position:

$boldsymbol\left\{ v\right\} = frac\left\{mathrm\left\{d\right\}boldsymbol\left\{ r\right\}\right\}\left\{mathrm\left\{d\right\}t\right\} = frac\left\{mathrm\left\{d\right\} \left(x hat \left\{mathbf\left\{ i\right\}\right\}\right)\right\}\left\{mathrm\left\{d\right\}t\right\} + frac\left\{mathrm\left\{d\right\} \left(y hat \left\{mathbf\left\{ j\right\}\right\}\right)\right\}\left\{mathrm\left\{d\right\}t\right\}$

By the product rule, this is:

$boldsymbol\left\{ v\right\} = dot x hat \left\{mathbf\left\{ i\right\}\right\} + x dot\left\{ hat \left\{mathbf\left\{ i\right\}\right\}\right\} + dot y hat \left\{mathbf\left\{ j\right\}\right\} + y dot\left\{ hat \left\{mathbf\left\{ j\right\}\right\}\right\}$

Which from the identities above we know to be:

$boldsymbol\left\{ v\right\} = dot x hat \left\{mathbf\left\{ i\right\}\right\} + x omega hat \left\{mathbf\left\{ j\right\}\right\} + dot y hat \left\{mathbf\left\{ j\right\}\right\} - y omega hat \left\{mathbf\left\{ i\right\}\right\} = \left(dot x - y omega\right) hat \left\{mathbf\left\{ i\right\}\right\} + \left(dot y + x omega\right) hat \left\{mathbf\left\{ j\right\}\right\}$

or equivalently

$boldsymbol\left\{ v\right\}= \left(dot x hat \left\{mathbf\left\{ i\right\}\right\} + dot y hat \left\{mathbf\left\{ j\right\}\right\}\right) + \left(y dot\left\{ hat \left\{mathbf\left\{ j\right\}\right\}\right\} + x dot\left\{hat \left\{mathbf\left\{ i\right\}\right\}\right\}\right) = boldsymbol\left\{ v\right\}_\left\{rel\right\} + boldsymbol\left\{Omega\right\} times boldsymbol\left\{r\right\}$

where vrel is the velocity of the particle relative to the rotating coordinate system.

##### Acceleration
Acceleration is the time derivative of velocity.

We know that:

$boldsymbol\left\{ a\right\} = frac\left\{mathrm\left\{d\right\}\right\}\left\{mathrm\left\{d\right\}t\right\} boldsymbol\left\{ v\right\}$
= frac{mathrm{d} boldsymbol{ v}_{rel}}{mathrm{d}t} + frac{mathrm{d}}{mathrm{d}t} boldsymbol{Omega} times boldsymbol{r}

Consider the $stackrel\left\{frac\left\{ mathrm\left\{d\right\} \right\} \left\{ mathrm\left\{d\right\} t \right\}\right\}\left\{\right\}$$boldsymbol\left\{ v\right\}_\left\{rel\right\}$ part. $boldsymbol\left\{ v\right\}_\left\{rel\right\}$ has two parts we want to find the derivative of: the relative change in velocity ($boldsymbol\left\{ a\right\}_\left\{rel\right\}$), and the change in the coordinate frame ($boldsymbol\left\{Omega\right\} times boldsymbol\left\{ v\right\}_\left\{rel\right\}$).

$frac\left\{mathrm\left\{d\right\} boldsymbol\left\{ v\right\}_\left\{rel\right\}\right\}\left\{mathrm\left\{d\right\}t\right\} = boldsymbol\left\{ a\right\}_\left\{rel\right\} + boldsymbol\left\{Omega\right\} times boldsymbol\left\{ v\right\}_\left\{rel\right\}$

Next, consider $stackrel\left\{frac\left\{mathrm\left\{d\right\}\right\}\left\{mathrm\left\{d\right\}t\right\}\right\}\left\{\right\}$$\left(boldsymbol\left\{Omega\right\} timesboldsymbol\left\{ r\right\}\right)$. Using the chain rule:

$frac\left\{mathrm\left\{d\right\} \left(boldsymbol\left\{Omega\right\} times boldsymbol\left\{ r\right\}\right)\right\}\left\{mathrm\left\{d\right\}t\right\} = dot\left\{boldsymbol\left\{Omega\right\}\right\} times boldsymbol\left\{ r\right\} + boldsymbol\left\{Omega\right\} times dot\left\{boldsymbol\left\{ r\right\}\right\}$

$dot\left\{boldsymbol\left\{ r\right\}\right\}=boldsymbol\left\{ v\right\}=boldsymbol\left\{ v\right\}_\left\{rel\right\} + boldsymbol\left\{Omega\right\} times boldsymbol\left\{ r\right\}$ from above:

$frac\left\{mathrm\left\{d\right\} \left(boldsymbol\left\{Omega\right\} times boldsymbol\left\{ r\right\}\right)\right\}\left\{mathrm\left\{d\right\}t\right\} =$
dot{boldsymbol{Omega}} times boldsymbol{ r} + boldsymbol{Omega} times (boldsymbol{Omega} timesboldsymbol{ r}) + boldsymbol{Omega} times boldsymbol{ v}_{rel}

So all together:

$boldsymbol\left\{ a\right\} = boldsymbol\left\{ a\right\}_\left\{rel\right\} + boldsymbol\left\{Omega\right\} times boldsymbol\left\{ v\right\}_\left\{rel\right\} +$
dot{boldsymbol{Omega}} times boldsymbol{ r} + boldsymbol{Omega} times (boldsymbol{Omega} times boldsymbol{ r}) + boldsymbol{Omega} times boldsymbol{ v}_{rel}

And collecting terms:

$boldsymbol\left\{ a\right\} = boldsymbol\left\{ a\right\}_\left\{rel\right\} + 2\left(boldsymbol\left\{Omega\right\} times boldsymbol\left\{ v\right\}_\left\{rel\right\}\right) +$
dot{boldsymbol{Omega}} times boldsymbol{ r} + boldsymbol{Omega} times (boldsymbol{Omega} times boldsymbol{ r}) .

## Kinematic constraints

A kinematic constraint is any condition relating properties of a dynamic system that must hold true at all times. Below are some common examples:

### Rolling without slipping

An object that rolls against a surface without slipping obeys the condition that the velocity of its center of mass is equal to the cross product of its angular velocity with a vector from the point of contact to the center of mass,

$boldsymbol\left\{ v\right\}_G\left(t\right) = boldsymbol\left\{Omega\right\} times boldsymbol\left\{ r\right\}_\left\{G/O\right\}$.
For the case of an object that does not tip or turn, this reduces to v = R ω.

### Inextensible cord

This is the case where bodies are connected by some cord that remains in tension and cannot change length. The constraint is that the sum of all components of the cord is the total length, and the time derivative of this sum is zero.