In
mathematics, the
integral test for convergence is a method used to test infinite
series of
non-negative terms for
convergence. An early form of the test of convergence was developed in
India by
Madhava in the
14th century, and by his followers at the
Kerala School. In Europe, it was later developed by
Maclaurin and
Cauchy and is sometimes known as the Maclaurin–Cauchy test.
Statement of the test
Consider an
integer N and a non-negative
monotone decreasing function
f defined on the unbounded
interval [
N, ∞). Then the series
converges if and only if the integral
is finite. In particular, if the integral diverges, then the series diverges as well.
Proof
The proof basically uses the
comparison test, comparing the term
f(
n) with the integral of
f over the intervals [
n − 1,
n] and [
n,
n + 1], respectively.
Since f is a monotone decreasing function, we know that
f(x)le f(n)quadtext{for }xin[n,infty)
and
f(n)le f(x)quadtext{for }xin[N,n],
hence for every
n larger than
N
int_n^{n+1} f(x),dx
leint_{n}^{n+1} f(n),dx
=f(n)
=int_{n-1}^{n} f(n),dx
leint_{n-1}^n f(x),dx.
Since the lower estimate is also valid for
f(
N), we get by summation over all
n from
N to some larger integer
M
int_N^{M+1}f(x),dxlesum_{n=N}^MF(n)le f(N)+int_N^M f(x),dx.
Letting
M tend to infinity, the result follows.
Applications
The
harmonic series
sum_{n=1}^infty frac1n
diverges because, using the
natural logarithm, its
derivative, and the
fundamental theorem of calculus, we get
int_1^Mfrac1x,dx=ln xBigr|_1^M=ln Mtoinfty
quadtext{for }Mtoinfty.
Contrary, the series
sum_{n=1}^infty frac1{n^{1+varepsilon}}
(cf.
Riemann zeta function)
converges for every
ε > 0, because
int_1^Mfrac1{x^{1+varepsilon}},dx
-frac1{varepsilon x^varepsilon}biggr|_1^M
frac1varepsilonBigl(1-frac1{M^varepsilon}Bigr)
lefrac1varepsilon
quadtext{for all }Mge1.
Borderline between divergence and convergence
The above examples involving the harmonic series raise the question, whether there are monotone sequences such that
f(
n) decreases to 0 faster than 1/
n but slower than 1/
n1+ε in the sense that
lim_{ntoinfty}frac{f(n)}{1/n}=0
quadtext{and}quad
lim_{ntoinfty}frac{f(n)}{1/n^{1+varepsilon}}=infty
for every
ε > 0, and whether the corresponding series of the
f(
n) still diverges. Once such a sequence is found, a similar question can be asked with
f(
n) taking the role of 1/
n, and so on. In this way it is possible to investigate the borderline between divergence and convergence.
Using the integral test for convergence, one can show (see below) that, for every natural number k, the series
sum_{n=N_k}^inftyfrac1{nln(n)ln_2(n)cdots ln_{k-1}(n)ln_k(n)}
still diverges (cf.
proof that the sum of the reciprocals of the primes diverges for
k = 1) but
sum_{n=N_k}^inftyfrac1{nln(n)ln_2(n)cdotsln_{k-1}(n)(ln_k(n))^{1+varepsilon}}
converges for every
ε > 0. Here ln
k denotes the
k-fold
composition of the natural logarithm defined
recursively by
ln_k(x)=
begin{cases}
ln(x)&text{for }k=1,
ln(ln_{k-1}(x))&text{for }kge2.
end{cases}
Furthermore,
Nk denotes the smallest natural number such that the
k-fold composition is well-defined and ln
k Nk ≥ 1, i.e.
N_kge underbrace{e^{e^{cdot^{cdot^{e}}}}}_{k e'text{s}}=e uparrowuparrow k
using
tetration or
Knuth's up-arrow notation.
To see the divergence of the first series using the integral test, note that by repeated application of the chain rule
frac{d}{dx}ln_{k+1}(x)
=frac{d}{dx}ln(ln_k(x))
=frac1{ln_k(x)}frac{d}{dx}ln_k(x)
=cdots
=frac1{xln(x)cdotsln_k(x)},
hence
int_{N_k}^inftyfrac{dx}{xln(x)cdotsln_k(x)}
ln_{k+1}(x)bigr|_{N_k}^infty
infty.
To see the convergence of the second series, note that by the
power rule, the chain rule and the above result
-frac{d}{dx}frac1{varepsilon(ln_k(x))^varepsilon}
=frac1{(ln_k(x))^{1+varepsilon}}frac{d}{dx}ln_k(x)
=cdots
=frac{1}{xln(x)cdotsln_{k-1}(x)(ln_k(x))^{1+varepsilon}},
hence
int_{N_k}^inftyfrac{dx}{xln(x)cdotsln_{k-1}(x)(ln_k(x))^{1+varepsilon}}
=-frac1{varepsilon(ln_k(x))^varepsilon}biggr|_{N_k}^infty
References
- Knopp, Konrad, "Infinite Sequences and Series", Dover publications, Inc., New York, 1956. (§ 3.3) ISBN 0-486-60153-6
- Whittaker, E. T., and Watson, G. N., A Course in Modern Analysis, fourth edition, Cambridge University Press, 1963. (§ 4.43) ISBN 0-521-58807-3