The algorithm is identical to the Ford-Fulkerson algorithm, except that the search order when finding the augmenting path is defined. The path found must be the shortest path which has available capacity. This can be found by a breadth-first search, as we let edges have unit length. The running time of is found by showing that each augmenting path can be found in time, that every time at least one of the edge becomes saturated, that the distance from the saturated edge to the source along the augmenting path must be longer than last time it was saturated, and that the distance is at most long. Another property of this algorithm is that the length of the shortest augmenting path increases monotonically. There is an accessible proof in .
algorithm EdmondsKarp
input:
C[1..n, 1..n] (Capacity matrix)
E[1..n, 1..?] (Neighbour lists)
s (Source)
t (Sink)
output:
f (Value of maximum flow)
F (A matrix giving a legal flow with the maximum value)
f := 0 (Initial flow is zero)
F := array(1..n, 1..n) (Residual capacity from u to v is C[u,v] - F[u,v])
forever
m, P := BreadthFirstSearch(C, E, s, t)
if m = 0
break
f := f + m
(Backtrack search, and write flow)
v := t
while v ≠ s
u := P[v]
F[u,v] := F[u,v] + m
F[v,u] := F[v,u] - m
v := u
return (f, F)
algorithm BreadthFirstSearch
input:
C, E, s, t
output:
M[t] (Capacity of path found)
P (Parent table)
P := array(1..n)
for u in 1..n
P[u] := -1
P[s] := -2 (make sure source is not rediscovered)
M := array(1..n) (Capacity of found path to node)
M[s] := ∞
Q := queue()
Q.push(s)
while Q.size() > 0
u := Q.pop()
for v in E[u]
(If there is available capacity, and v is not seen before in search)
if C[u,v] - F[u,v] > 0 and P[v] = -1
P[v] := u
M[v] := min(M[u], C[u,v] - F[u,v])
if v ≠ t
Q.push(v)
else
return M[t], P
return 0, P
Given a network of seven nodes, source A, sink G, and capacities as shown below:
In the pairs written on the edges, is the current flow, and is the capacity. The residual capacity from to is , the total capacity, minus the flow that is already used. If the net flow from to is negative, it contributes to the residual capacity.
| Capacity | Path |
|---|---|
| Resulting network | |
Notice how the length of the augmenting path found by the algorithm (in red) never decreases. The paths found are the shortest possible. The flow found is equal to the capacity across the minimum cut in the graph separating the source and the sink. There is only one minimal cut in this graph, partitioning the nodes into the sets and , with the capacity .
public FlowGraph(String fileName)
{
.. // Read "size" value, "capacity[size][size]" matrix,
// as well as "source" and "sink" node indexes (0-based)
// from an input text file.
maxFlow();
} private void maxFlow() // Edmonds-Karp algorithm with O(V³E) complexity
{
flow = new double[size][size];
res_capacity = new double[size][size];
parent = new int[size];
min_capacity = new double[size];
color = new int[size];
queue = new int[size];
for (int i = 0; i < size; i++)
for (int j = 0; j < size; j++)
res_capacity[i][j] = capacity[i][j];
while (BFS(source))
{
max_flow += min_capacity[sink];
int v = sink, u;
while (v != source)
{
u = parent[v];
flow[u][v] += min_capacity[sink];
flow[v][u] -= min_capacity[sink];
res_capacity[u][v] -= min_capacity[sink];
res_capacity[v][u] += min_capacity[sink];
v = u;
}
}
} private boolean BFS(int source) // Breadth First Search in O(V²)
{
for (int i = 0; i < size; i++)
{
color[i] = WHITE;
min_capacity[i] = Double.MAX_VALUE;
}
first = last = 0;
queue[last++] = source;
color[source] = GRAY;
while (first != last) // While "queue" not empty..
{
int v = queue[first++];
for (int u = 0; u < size; u++)
if (color[u] == WHITE && res_capacity[v][u] > 0)
{
min_capacity[u] = Math.min(min_capacity[v], res_capacity[v][u]);
parent[u] = v;
color[u] = GRAY;
if (u == sink) return true;
queue[last++] = u;
}
}
return false;
} public void toFile(String fileName)
{
.. // Write the results ("flow" matrix and "max_flow" value) to output file.
// To be called in the "main()" method.
}
}