In
poker , the
probability of many
events can be determined by direct calculation. This article discusses how to compute the probabilities for many commonly occurring events in the game of
Texas hold 'em and provides some
probabilities and
odds for specific situations. In most cases, the probabilities and odds are
approximations due to
rounding .
When calculating probabilities for a card game such as Texas Hold 'em, there are two basic approaches. the first approach is to determine the number of outcomes that satisfy the condition being evaluated and divide this by the total number of possible outcomes .
For example, there are six outcomes (ignoring order) for being dealt a pair of aces in Hold' em:
{A♣ , A♥ A♠ , A♦ A♠ , A♣ },
{A♥ A♦ A♥ A♠ }, and
{A♦ A♣ }.
There are 52 ways to pick the first card and 51 ways to pick the second card and two ways to order the two cards yielding (52×51)/2=1326 possible outcomes when being dealt two cards (also ignoring order).
This gives a probability of being dealt two aces of begin{matrix} frac{6}{1326} = frac{1}{221} end{matrix}.
The second approach is to use conditional probabilities , or in more complex situations, a decision tree . There are 4 ways to be dealt an ace out of 52 choices for the first card resulting in a probability of begin{matrix} frac{4}{52} = frac{1}{13} end{matrix}. There are 3 ways of getting dealt an ace out of 51 choices on the second card after being dealt an ace on the first card for a probability of begin{matrix} frac{3}{51} = frac{1}{17} end{matrix}. The conditional probability of being dealt two aces is the product of the two probabilities: begin{matrix} frac{1}{13} times frac{1}{17} = frac{1}{221} end{matrix}. (Note that in this case the total is not divided by 2 ways of ordering the cards because both cards must be an ace. Reordering would still require the first and second cards to be an ace, so there is only one way to order the two cards.)
Often, the key to determining probability is selecting the best approach for a given problem. This article uses both of these approaches.
Starting hands The probability of being dealt various starting hands can be explicitly calculated. In Texas Hold 'em, a player is dealt two down (or hole or pocket ) cards. The first card can be any one of 52 playing cards in the deck and the second card can be any one of the 51 remaining cards. This gives 52 × 51 ÷ 2 = 1,326 possible starting hand combinations. (Since the order of the cards is not significant, the 2,652 permutations are divided by the 2 ways of ordering two cards.) Alternatively, the number of possible starting hands is represented as the binomial coefficient
{52 choose 2} = 1,326 which is the number of possible combinations of choosing 2 cards from a deck of 52 playing cards.
The 1,326 starting hands can be reduced for purposes of determining the probability of starting hands for Hold 'em—since suits have no relative value in poker, many of these hands are identical in value before the flop . The only factors determining the strength of a starting hand are the ranks of the cards and whether the cards share the same suit. Of the 1,326 combinations, there are 169 distinct starting hands grouped into three shapes: 13 pocket pairs (paired hole cards), 13 × 12 ÷ 2 = 78 suited hands and 78 unsuited hands; 13 + 78 + 78 = 169. The relative probability of being dealt a hand of each given shape is different. The following shows the probabilities and odds of being dealt each type of starting hand.
Hand shape
Number Suit combinations Combinations
Dealt specific hand
Dealt any hand
Probability
Odds
Probability
Odds
Pocket pair
13
{4 choose 2} = 6
13 × 6 = 78
begin{matrix} frac{6}{1326} approx 0.00453 end{matrix}
220 : 1
begin{matrix} frac{78}{1326} approx 0.0588 end{matrix}
16 : 1
Suited cards
78
{4 choose 1} = 4
78 × 4 = 312
begin{matrix} frac{4}{1326} approx 0.00302 end{matrix}
331 : 1
begin{matrix} frac{312}{1326} approx 0.2353 end{matrix}
3.25 : 1
Unsuited cards
78
{4 choose 1}{3 choose 1} = 12
78 × 12 = 936
begin{matrix} frac{12}{1326} approx 0.00905 end{matrix}
110 : 1
begin{matrix} frac{936}{1326} approx 0.7059 end{matrix}
.417 : 1
Here are the probabilities and odds of being dealt various other types of starting hands.
Hand
Probability
Odds
AKs (or any specific suited cards)
0.00302
331 : 1
AA (or any specific pair)
0.00453
220 : 1
AKs, KQs, QJs, or JTs
0.0121
81.9 : 1
AK (or any specific non-pair incl. suited)
0.0121
81.9 : 1
AA, KK, or QQ
0.0136
72.7 : 1
AA, KK, QQ or JJ
0.0181
54.3 : 1
Suited cards, jack or better
0.0181
54.3 : 1
AA, KK, QQ, JJ, or TT
0.0226
43.2 : 1
Suited cards, 10 or better
0.0302
32.2 : 1
Suited connectors
0.0392
24.5 : 1
Connected cards, 10 or better
0.0483
19.7 : 1
Any 2 cards with rank at least queen
0.0498
19.1 : 1
Any 2 cards with rank at least jack
0.0905
10.1 : 1
Any 2 cards with rank at least 10
0.143
5.98 : 1
Connected cards (cards of consecutive rank)
0.157
5.38 : 1
Any 2 cards with rank at least 9
0.208
3.81 : 1
Not connected nor suited, at least one 2-9
0.534
0.873 : 1
Starting hands heads up For any given starting hand, there are 50 × 49 ÷ 2 = 1,225 hands that an opponent can have before the flop. (After the flop, the number of possible hands an opponent can have is reduced by the three community cards revealed on the flop to 47 × 46 ÷ 2 = 1,081 hands.) Therefore, there are
{52 choose 2}{50 choose 2} div 2 = 812,175 possible head-to-head match ups in Hold 'em. (The total number of match ups is divided by the two ways that two hands can be distributed between two players to give the number of unique match ups.) However, since there are only 169 distinct starting hands, there are 169 × 1,225 = 207,025 distinct head-to-head match ups.
It is useful and interesting to know how two starting hands compete against each other heads up before the flop. In other words, we assume that neither hand will fold, and we will see a showdown. This situation occurs quite often in no limit and tournament play. Also, studying these odds helps to demonstrate the concept of hand domination , which is important in all community card games.
This problem is considerably more complicated than determining the frequency of dealt hands. To see why, note that given both hands, there are 48 remaining unseen cards. Out of these 48 cards, we can choose any 5 to make a board. Thus, there are
{48 choose 5} = 1,712,304 possible boards that may fall. In addition to determining the precise number of boards that give a win to each player, we also must take into account boards which split the pot, and split the number of these boards between the players.
The problem is trivial for computers to solve by brute force search ; there are many software programs available that will compute the odds in seconds. A somewhat less trivial exercise is an exhaustive analysis of all of the head-to-head match ups in Texas Hold 'em, which requires evaluating each possible board for each distinct head-to-head match up, or 1,712,304 × 207,025 = 354,489,735,600 (≈354 billion ) results.
Head-to-head starting hand matchups When comparing two starting hands, the head-to-head probability describes the likelihood of one hand beating the other after all of the cards have come out. Head-to-head probabilities vary slightly for each particular distinct starting hand matchup, but the approximate average probabilities, as given by Dan Harrington in Harrington on Hold'em [p.125], are summarized in the following table.
Favourite-to-underdog matchup
Probability
Odds for
Pair vs. 2 undercards
0.83
4.9 : 1
Pair vs. lower pair
0.82
4.5 : 1
Pair vs. 1 overcard, 1 undercard
0.71
2.5 : 1
2 overcards vs. 2 undercards
0.63
1.7 : 1
Pair vs. 2 overcards
0.55
1.2 : 1
These odds are general approximations only derived from averaging all of the hand matchups in each category. The actual head-to-head probabilities for any two starting hands vary depending on a number of factors, including:
Suited or unsuited starting hands;
Shared suits between starting hands;
Connectedness of non-pair starting hands;
Proximity of card ranks between the starting hands (lowering straight potential);
Proximity of card ranks toward A or 2 (lowering straight potential);
Possibility of split pot.
For example, A♠ A♣ vs. K♠ Q♣ is 87.65% to win (0.49% to split), but A♠ A♣ vs. 7♦ 6♦
The mathematics for computing all of the possible matchups is quite complex. However, a computer program can perform a brute force evaluation of the 1,712,304 possible boards for any given pair of starting hands in seconds.
Starting hands against multiple opponents When facing two opponents, for any given starting hand the number of possible combinations of hands the opponents can have is
{50 choose 2}{48 choose 2} = 1,381,800 hands. For calculating probabilities we can ignore the distinction between the two opponents holding A♠ J♥ 8♥ 8♣ and the opponents holding 8♥ 8♣ and A♠ J♥ n opponents is n! (the factorial of n). So the number of unique hand combinations H against two opponents is
H = {50 choose 2}{48 choose 2} div 2! = 690,900, and against three opponents is
H = {50 choose 2}{48 choose 2}{46 choose 2} div 3! = 238,360,500, and against n opponents is
H = prod_{k=1}^n {52 - 2k choose 2} div k!, or alternatively H = {50 choose 2n} times (2n-1)
, It is important to note here that x
is not the same as (x!)!, click the link just below to see the calculationwhere (2n-1)
(
is the double factorial operator) is the number of ways to distribute 2n cards between n hands of two cards each. The following table shows the number of hand combinations for up to nine opponents.
Opponents
Number of possible hand combinations
1
1,225
2
690,900
3
238,360,500
4
56,372,258,250
5
≈9.7073 × 1012 (more than 9 trillion )
6
≈1.2620 × 1015 (more than 1 quadrillion )
7
≈1.2674 × 1017 (more than 126 quadrillion)
8
≈9.9804 × 1018 (almost 10 quintillion )
9
≈6.2211 × 1020 (more than 622 quintillion)
An exhaustive analysis of all of the match ups in Texas Hold 'em of a player against nine opponents requires evaluating each possible board for each distinct starting hand against each possible combination of hands held by nine opponents, which is
169 times {50 choose 18} times 17
times {32 choose 5} approx 2.117 times 10^{28} (more than 21 octillion ). If you were able to evaluate one trillion (1012 ) combinations every second, it would take over 670 million years to evaluate all of the hand/board combinations. While it is possible to significantly reduce the total number of combinations by pruning combinations with identical properties, the total number of situations is still well beyond the number that can be evaluated by brute force. For this reason, most software programs compute probabilities and expected values for Hold 'em poker hands against multiple opponents by simulating the play of thousands or even millions of hands to determine statistical probabilities .
Dominated hands When evaluating a hand before the flop, it is useful to have some idea of how likely the hand is dominated dominant hand) and is extremely unlikely to win against it. Often the dominated hand has only a single card rank that can improve the dominated hand to beat the dominant hand (not counting straights and flushes). For example, KJ is dominated by KQ —both hands share the king and the queen kicker is beating the jack kicker. Barring a straight or flush, the KJ will need a jack on the board to improve against the KQ (and will still be losing if a queen comes on the board also). A pocket pair is dominated by a pocket pair of higher rank.
Pocket pairs Barring a straight or flush, a pocket pair needs to make three of a kind to beat a higher pocket pair. See the section "After the flop " for the odds of a pocket pair improving to three of a kind.
To calculate the probability that another player has a higher pocket pair, first consider the case against a single opponent. The probability that a single opponent has a higher pair can be stated as the probability that the first card dealt to the opponent is a higher rank than the pocket pair and the second card is the same rank as the first. Where r r ) × 4 cards of higher rank. Subtracting the two cards for the pocket pair leaves 50 cards in the deck. After the first card is dealt to the player there are 49 cards left, 3 of which are the same rank as the first. So the probability P of a single opponent being dealt a higher pocket pair is
P = frac{(14 - r) times 4}{50} times frac{3}{49}
= frac{84 - 6r}{1225}.
The following approach extends this equation to calculate the probability that one or more other players has a higher pocket pair.
Multiply the base probability for a single player for a given rank of pocket pairs by the number of opponents in the hand;
Subtract the adjusted probability that more than one opponent has a higher pocket pair. (This is necessary because this probability effectively gets added to the calculation multiple times when multiplying the single player result.)
Where n P_{ma}
P = left(frac{84 - 6r}{1225}right) times n - P_{ma}. The calculation for P_{ma} depends on the rank of the player's pocket pair, but can be generalized as
P_{ma} = P_2 + 2P_3 + cdots + (n-1)P_n, where P_2 P_3 2 s against 9 opponents, P_4 < 0.0015 and P_5 < 0.00009 , so just calculating P_2 and P_3 gives an adequately precise result.
The following table shows the probability that before the flop another player has a larger pocket pair when there are one to nine other players in the hand.
Probability of facing a Against 1
Against 2
Against 3
Against 4
Against 5
Against 6
Against 7
Against 8
Against 9
KK
0.0049
0.0098
0.0147
0.0196
0.0244
0.0293
0.0342
0.0391
0.0439
QQ
0.0098
0.0195
0.0292
0.0388
0.0484
0.0579
0.0673
0.0766
0.0859
JJ
0.0147
0.0292
0.0436
0.0577
0.0717
0.0856
0.0992
0.1127
0.1259
TT
0.0196
0.0389
0.0578
0.0764
0.0946
0.1124
0.1299
0.1470
0.1637
99
0.0245
0.0484
0.0718
0.0946
0.1168
0.1384
0.1593
0.1795
0.1990
88
0.0294
0.0580
0.0857
0.1125
0.1384
0.1634
0.1873
0.2101
0.2318
77
0.0343
0.0674
0.0994
0.1301
0.1595
0.1874
0.2138
0.2387
0.2619
66
0.0392
0.0769
0.1130
0.1473
0.1799
0.2104
0.2389
0.2651
0.2890
55
0.0441
0.0862
0.1263
0.1642
0.1996
0.2324
0.2623
0.2892
0.3129
44
0.0490
0.0956
0.1395
0.1806
0.2186
0.2532
0.2841
0.3109
0.3334
33
0.0539
0.1048
0.1526
0.1967
0.2370
0.2729
0.3040
0.3300
0.3503
22
0.0588
0.1141
0.1654
0.2124
0.2546
0.2914
0.3222
0.3464
0.3633
The following table gives the probability that a hand is facing two or more larger pairs before the flop. From the previous equations, the probability P_m is computed as
P_m = P_2 + P_3 + cdots + P_n.
Probability of facing multiple Against 2
Against 3
Against 4
Against 5
Against 6
Against 7
Against 8
Against 9
KK
< 0.00001
0.00001
0.00003
0.00004
0.00007
0.00009
0.00012
0.00016
QQ
0.00006
0.00018
0.00037
0.00061
0.00091
0.00128
0.00171
0.00220
JJ
0.00017
0.00051
0.00102
0.00171
0.00257
0.00360
0.00482
0.00621
TT
0.00033
0.00099
0.00200
0.00335
0.00504
0.00709
0.00950
0.01226
99
0.00054
0.00164
0.00330
0.00553
0.00836
0.01177
0.01580
0.02045
88
0.00081
0.00244
0.00493
0.00828
0.01253
0.01769
0.02378
0.03084
77
0.00112
0.00341
0.00689
0.01160
0.01758
0.02487
0.03351
0.04353
66
0.00149
0.00454
0.00918
0.01550
0.02353
0.03335
0.04503
0.05861
55
0.00191
0.00583
0.01182
0.01998
0.03040
0.04318
0.05840
0.07619
44
0.00239
0.00728
0.01480
0.02506
0.03821
0.05438
0.07371
0.09635
33
0.00291
0.00890
0.01812
0.03075
0.04698
0.06699
0.09099
0.11919
22
0.00349
0.01068
0.02180
0.03706
0.05673
0.08107
0.11034
0.14484
From a practical perspective, however, the odds of out drawing a single pocket pair or multiple pocket pairs are not much different. In both cases the large majority of winning hands require one of the remaining two cards needed to make three of a kind . The real difference against multiple overpairs becomes the increased probability that one of the overpairs will also make three of a kind.
Hands with one ace When holding a single ace (referred to as Ax ), it is useful to know how likely it is that another player has a better ace —an ace with a higher second card. The weaker ace is dominated by the better ace. The probability that a single opponent has a better ace is the probability that he has either AA or Ax where x is a rank other than ace that is higher than the player's second card. When holding Ax , the probability that a chosen single player has AA is begin{matrix} frac{3}{50} times frac{2}{49} approx 0.00245 end{matrix} . In the case of a table with n one of them holding AA is (1-(1-0.00245)^n) . If the player is holding Ax against 9 opponents, there is a probability of approximately 0.0218 that one opponent has AA .
Where x is the rank 2–K of the second card (assigning values from 2–10 and J–K = 11–13) the probability that a single opponent has a better ace is calculated by the formula
P = left(frac{3}{50} times frac{2}{49}right) + left(frac{3}{50} times frac{(13 - x) times 4}{49} times 2right)
= frac{3}{1225} + frac{12 times (13 - x)}{1225}
= frac{159 - 12x}{1225}.
The probability begin{matrix} frac{3}{50} times frac{(13 - x) times 4}{49} end{matrix} of a player having Ay , where y is a rank such that x < y <= K , is multiplied by the two ways to order the cards A and y in the hand.
The following table shows the probability that before the flop another player has an ace with a larger kicker in the hand.
Probability of facing an ace Against 1
Against 2
Against 3
Against 4
Against 5
Against 6
Against 7
Against 8
Against 9
AK
0.00245
0.00489
0.00733
0.00976
0.01219
0.01460
0.01702
0.01942
0.02183
AQ
0.01224
0.02434
0.03629
0.04809
0.05974
0.07126
0.08263
0.09386
0.10496
AJ
0.02204
0.04360
0.06468
0.08529
0.10545
0.12517
0.14445
0.16331
0.18175
AT
0.03184
0.06266
0.09250
0.12139
0.14937
0.17645
0.20267
0.22805
0.25263
A9
0.04163
0.08153
0.11977
0.15642
0.19154
0.22520
0.25745
0.28837
0.31799
A8
0.05143
0.10021
0.14649
0.19038
0.23202
0.27152
0.30898
0.34452
0.37823
A7
0.06122
0.11870
0.17266
0.22331
0.27086
0.31550
0.35741
0.39675
0.43369
A6
0.07102
0.13700
0.19829
0.25523
0.30812
0.35726
0.40291
0.44531
0.48471
A5
0.08082
0.15510
0.22338
0.28615
0.34384
0.39687
0.44561
0.49041
0.53160
A4
0.09061
0.17301
0.24795
0.31609
0.37806
0.43442
0.48567
0.53227
0.57465
A3
0.10041
0.19073
0.27199
0.34509
0.41085
0.47000
0.52322
0.57109
0.61416
A2
0.11020
0.20826
0.29552
0.37315
0.44223
0.50370
0.55840
0.60706
0.65037
The flop The value of a starting hand can change dramatically after the flop. Regardless of initial strength, any hand can flop the nuts —for example, if the flop comes with three 2 s, any hand holding the fourth 2 has the nuts (though additional cards could still give another player a higher four of a kind or a straight flush). Conversely, the flop can undermine the perceived strength of any hand—a player holding A♣ A♥ 8♠ 9♠ 10♠ on the flop because of the straight and flush possibilities.
There are
{50 choose 3} = 19,600 possible flops for any given starting hand. By the turn the total number of combinations has increased to
{50 choose 4} = 230,300 and on the river there are
{50 choose 5} = 2,118,760 possible boards to go with the hand.
The following are some general probabilities about what can occur on the board. These assume a "random " starting hand for the player.
Board consisting of
Making on flop
Making by turn
Making by river
Prob.
Odds
Prob.
Odds
Prob.
Odds
Three or more of same suit
0.05177
18.3 : 1
0.13522
6.40 : 1
0.23589
3.24 : 1
Four or more of same suit
0.01056
93.7 : 1
0.03394
28.5 : 1
Rainbow flop (all different suits)
0.39765
1.51 : 1
0.10550
8.48 : 1
Three cards of consecutive rank (but not four consecutive)
0.03475
27.8 : 1
0.11820
7.46 : 1
0.25068
2.99 : 1
Four cards to a straight (but not five)
0.03877
24.8 : 1
0.18991
4.27 : 1
Three or more cards of consecutive rank and same suit
0.00217
459 : 1
0.00869
114 : 1
0.02172
45.0 : 1
Three of a kind (but not a full house or four of a kind)
0.00235
424 : 1
0.00935
106 : 1
0.02128
46 : 1
A pair (but not two pair or three or four of a kind)
0.16941
4.90 : 1
0.30417
2.29 : 1
0.42450
1.36 : 1
Two pair (but not a full house)
0.01037
95.4 : 1
0.04716
20.2 : 1
An interesting fact to note from the table above is that more than 60% of the flops will have at least two of the same suit—you're likely to either be drawing to a flush or worried about one.
Flopping overcards when holding a pocket pair It is also useful to look at the chances different starting hands have of either improving on the flop, or of weakening on the flop. One interesting circumstance concerns pocket pairs. When holding a pocket pair, overcards (cards of higher rank than the pair) weaken the hand because of the potential that an overcard has paired a card in an opponent's hand. The hand gets worse the more overcards there are on the board and the more opponents that are in the hand because the probability that one of the overcards has paired a hole card increases. To calculate the probability of no overcard, take the total number of outcomes without an overcard divided by the total number of outcomes.
Where x begin{matrix}(14 - x) times 4end{matrix} and the number of cards or rank x of less is begin{matrix}50 - (14 - x) times 4 = 4x - 6end{matrix} . The number of outcomes without an overcard is the number of combinations that can be formed with the remaining cards, so the probability P of an overcard on the flop is
P = {(4x - 6) choose 3} div {50 choose 3}, and on the turn and river are
P = {(4x - 6) choose 4} div {50 choose 4} and P = {(4x - 6) choose 5} div {50 choose 5}, respectively.The following table gives the probability that no overcards will come on the flop, turn and river, for each of the pocket pairs from 3 to K .
Holding pocket pair
No overcard on flop
No overcard by turn
No overcard by river
Prob.
Odds
Prob.
Odds
Prob.
Odds
KK
0.7745
0.29 : 1
0.7086
0.41 : 1
0.6470
0.55 : 1
QQ
0.5857
0.71 : 1
0.4860
1.06 : 1
0.4015
1.49 : 1
JJ
0.4304
1.32 : 1
0.3205
2.12 : 1
0.2369
3.22 : 1
TT
0.3053
2.28 : 1
0.2014
3.97 : 1
0.1313
6.61 : 1
99
0.2071
3.83 : 1
0.1190
7.40 : 1
0.0673
13.87 : 1
88
0.1327
6.54 : 1
0.0649
14.40 : 1
0.0310
31.21 : 1
77
0.0786
11.73 : 1
0.0318
30.48 : 1
0.0124
79.46 : 1
66
0.0416
23.02 : 1
0.0133
74.26 : 1
0.0040
246.29 : 1
55
0.0186
52.85 : 1
0.0043
229.07 : 1
0.0009
1,057.32 : 1
44
0.0061
162.33 : 1
0.0009
1,095.67 : 1
0.0001
8,406.78 : 1
33
0.0010
979.00 : 1
0.0001
15,352.33 : 1
0.0000
353,125.67 : 1
Notice that there is a better than 35% probability that an ace will come by the river if holding pocket kings, and with pocket queens, the odds are slightly in favor of an ace or a king coming by the turn, and a full 60% in favor of an overcard to the queen by the river. With pocket jacks, there's only a 43% chance that an overcard will not come on the flop and it is better than 3 : 1 that an overcard will come by the river.
Notice, though, that those probabilities would be lower if we consider that at least one opponent happens to hold one of those overcards.
After the flop During play—that is, from the flop and onwards—drawing probabilities come down to a question of outs . All situations which have the same number of outs have the same probability of improving to a winning hand over any unimproved hand held by an opponent. For example, an inside straight draw (e.g. 3-4-6-7 missing the 5 for a straight), and a full house draw (e.g. 6-6-K-K drawing for one of the pairs to become three-of-a-kind) are equivalent. Each can be satisfied by four cards—four 5 s in the first case, and the other two 6 s and other two kings in the second.
The probabilities of drawing these outs are easily calculated. At the flop there remain 47 unseen cards, so the probability is (outs ÷ 47). At the turn there are 46 unseen cards so the probability is (outs ÷ 46). The cumulative probability of making a hand on either the turn or river can be determined as the complement of the odds of not making the hand on the turn and not on the river. The probability of not drawing an out is (47 − outs) ÷ 47 on the turn and (46 − outs) ÷ 46 on the river; taking the complement of these conditional probabilities gives the probability of drawing the out by the river which is calculated by the formula
P = 1 - left(frac{47 - outs}{47} times frac{46 - outs}{46}right). For reference, the probability and odds for some of the more common numbers of outs are given here.
Example drawing to
Outs
Make on turn
Make on river
Make on turn or river
Prob.
Odds
Prob.
Odds
Prob.
Odds
Inside straight flush ; Four of a kind
1
0.0213
46.0 : 1
0.0217
45.0 : 1
0.0426
22.5 : 1
Open-ended straight flush; Three of a kind
2
0.0426
22.5 : 1
0.0435
22.0 : 1
0.0842
10.9 : 1
High pair
3
0.0638
14.7 : 1
0.0652
14.3 : 1
0.1249
7.01 : 1
Inside straight ; Full house
4
0.0851
10.8 : 1
0.0870
10.5 : 1
0.1647
5.07 : 1
Three of a kind or two pair
5
0.1064
8.40 : 1
0.1087
8.20 : 1
0.2035
3.91 : 1
Either pair
6
0.1277
6.83 : 1
0.1304
6.67 : 1
0.2414
3.14 : 1
Full house or four of a kind; (see note) 7
0.1489
5.71 : 1
0.1522
5.57 : 1
0.2784
2.59 : 1
Open-ended straight
8
0.1702
4.88 : 1
0.1739
4.75 : 1
0.3145
2.18 : 1
Flush
9
0.1915
4.22 : 1
0.1957
4.11 : 1
0.3497
1.86 : 1
Inside straight or pair
10
0.2128
3.70 : 1
0.2174
3.60 : 1
0.3839
1.60 : 1
Open-ended straight or high pair
11
0.2340
3.27 : 1
0.2391
3.18 : 1
0.4172
1.40 : 1
Inside straight or flush; Flush or high pair
12
0.2553
2.92 : 1
0.2609
2.83 : 1
0.4496
1.22 : 1
13
0.2766
2.62 : 1
0.2826
2.54 : 1
0.4810
1.08 : 1
Open-ended straight or pair
14
0.2979
2.36 : 1
0.3043
2.29 : 1
0.5116
0.955 : 1
Open-ended straight or flush; Flush or pair; 15
0.3191
2.13 : 1
0.3261
2.07 : 1
0.5412
0.848 : 1
16
0.3404
1.94 : 1
0.3478
1.88 : 1
0.5698
0.755 : 1
17
0.3617
1.76 : 1
0.3696
1.71 : 1
0.5976
0.673 : 1
Inside straight or flush or pair; 18
0.3830
1.61 : 1
0.3913
1.56 : 1
0.6244
0.601 : 1
19
0.4043
1.47 : 1
0.4130
1.42 : 1
0.6503
0.538 : 1
20
0.4255
1.35 : 1
0.4348
1.30 : 1
0.6753
0.481 : 1
Open-ended straight, flush or pair
21
0.4468
1.24 : 1
0.4565
1.19 : 1
0.6994
0.430 : 1
Note: When drawing to a full house or four of a kind with a pocket pair that has hit trips (three of a kind) on the flop, there are 6 outs to get a full house by pairing the board and one out to make four of a kind. This means that if the turn does not pair the board or make four of a kind, there will be 3 additional outs on the river, for a total of 10, to pair the turn card and make a full house. This makes the probability of drawing to a full house or four of a kind on the turn or river 0.334 and the odds are 1.99 : 1. This makes drawing to a full house or four of a kind by the river about 8½ outs.
It is worth noting in the preceding table that if a player doesn't fold before the river, a hand with at least 14 outs after the flop has a better than 50% chance to catch one of its outs by the river. With 20 or more outs, a hand is a better than 2 : 1 favorite to catch at least one out by the river.
See the article on pot odds for examples of how these probabilities might be used in gameplay decisions.
Estimating probability of drawing outs
Few poker players have the mathematical ability to calculate odds in the middle of a poker hand. One solution is to memorize the actual odds of drawing outs after the flop and after the turn, since these odds are needed frequently for making decisions.Another solution some players use is an easily-calculated approximation of the probability for drawing outs.
Approximating odds after the flop
With two cards to come, the percent chance of hitting one of x 4x . This approximation gives roughly accurate probabilities for up to about 12 outs, with an absolute average error of 0.9, a maximum absolute error of 3, a relative average error of 3.5, and a maximum relative error of 6.8.A slightly more complicated, but significantly more accurate approximation of drawing outs after the flop is to use 4x only for 1 to 9 outs, and (3x+9) for 10 or more outs. This approximation has a maximum absolute error of less than 1 for 1 to 19 outs and maximum relative error of less than 5 for 2 to 23 outs.
Approximating odds after the turn
With one card to come, the percent chance of hitting one of x A more accurate approximation is (2x+(2x÷10). This is easily done by first multiplying x
Chart: post-flop odds approximations
The following shows the approximations and their absolute and relative errors for both methods of approximation.
Outs
Make on turn or river
Make on river
Actual
(4x)%
(3x + 9)% x>9
Actual
(2x)%
(2x + (2x text{ ÷ } 10))%
Est.
Error
Error
Est.
Error
Error
Est.
Error
Error
Est.
Error
Error
1
4.2553
4
−0.26
6.00
2.1739
2
−0.17
8.00
2
−0.17
8.00
2
8.4181
8
−0.42
4.97
4.3478
4
−0.35
8.00
4
−0.35
8.00
3
12.4884
12
−0.49
3.91
6.5217
6
−0.52
8.00
7
+0.48
7.33
4
16.4662
16
−0.47
2.83
8.6957
8
−0.70
8.00
9
+0.30
3.50
5
20.3515
20
−0.35
1.73
10.8696
10
−0.87
8.00
11
+0.13
1.20
6
24.1443
24
−0.14
0.60
13.0435
12
−1.04
8.00
13
−0.04
0.33
7
27.8446
28
+0.16
0.56
15.2174
14
−1.22
8.00
15
−0.22
1.43
8
31.4524
32
+0.55
1.74
17.3913
16
−1.39
8.00
18
+0.61
3.50
9
34.9676
36
+1.03
2.95
19.5652
18
−1.57
8.00
20
+0.43
2.22
10
38.3904
40
+1.61
4.19
39
+0.61
1.59
21.7391
20
−1.74
8.00
22
+0.26
1.20
11
41.7206
44
+2.28
5.46
42
+0.28
0.67
23.9130
22
−1.91
8.00
24
+0.09
0.36
12
44.9584
48
+3.04
6.77
45
+0.04
0.09
26.0870
24
−2.09
8.00
26
−0.09
0.33
13
48.1036
52
+3.90
8.10
48
−0.10
0.22
28.2609
26
−2.26
8.00
29
+0.74
2.62
14
51.1563
56
+4.84
9.47
51
−0.16
0.31
30.4348
28
−2.43
8.00
31
+0.57
1.86
15
54.1166
60
+5.88
10.87
54
−0.12
0.22
32.6087
30
−2.61
8.00
33
+0.39
1.20
16
56.9843
64
+7.02
12.31
57
+0.02
0.03
34.7826
32
−2.78
8.00
35
+0.22
0.62
17
59.7595
68
+8.24
13.79
60
+0.24
0.40
36.9565
34
−2.96
8.00
37
+0.04
0.12
18
62.4422
72
+9.56
15.31
63
+0.56
0.89
39.1304
36
−3.13
8.00
40
+0.87
2.22
19
65.0324
76
+10.97
16.86
66
+0.97
1.49
41.3043
38
−3.30
8.00
42
+0.70
1.68
20
67.5301
80
+12.47
18.47
69
+1.47
2.18
43.4783
40
−3.48
8.00
44
+0.52
1.20
21
69.9352
84
+14.06
20.11
72
+2.06
2.95
45.6522
42
−3.65
8.00
46
+0.35
0.76
22
72.2479
88
+15.75
21.80
75
+2.75
3.81
47.8261
44
−3.83
8.00
48
+0.17
0.36
23
74.4681
92
+17.53
23.54
78
+3.53
4.74
50.0000
46
−4.00
8.00
51
+1.00
2.00
Either of these approximations is generally accurate enough to aid in most pot odds calculations.
Example of drawing outs The unseen cards principle states that to calculate the probability (from the point of view of a player about to act) that the next card dealt will be among a certain set, he must divide the number of cards in that set by the number of cards he has not seen, regardless of where those cards are. For example, a player playing five-card draw who holds 5-6-7-8-K wants to discard the K hoping to draw a 4 or 9 to complete a straight. He will calculate his probability of success on the turn as 8 ÷ 47: 4 4 s and 4 9 s give 8 outs, and 52 cards minus the 5 he has already seen make 47. The fact that some of those unseen cards may have already been dealt to other players is irrelevant, because he has no information about where the desired cards are, and must act based only upon information he does have. In a game among experts, it sometimes is possible to deduce what an opponent is probably holding, and adjust your odds computation. In a stud poker or community card poker game, cards that the player has seen because they are dealt face up are subtracted from the unseen card count (and from the set of desired cards as well if they are out of play).
Runner-runner outs Some outs for a hand require drawing an out on both the turn and the river—making two consecutive outs is called a runner-runner . Examples would be needing two cards to make a straight, flush, or three or four of a kind. Runner-runner outs can either draw from a common set of outs or from disjoint sets of outs. Two disjoint outs can either be conditional or independent events.
Common outs Drawing to a flush is an example of drawing from a common set of outs. Both the turn and river need to be the same suit, so both outs are coming from a common set of outs—the set of remaining cards of the desired suit. After the flop, if x is the number of common outs, the probability P of drawing runner-runner outs is
P = frac{x}{47} times frac{x-1}{46}. Since a flush would have 10 outs, the probability of a runner-runner flush draw is begin{matrix} frac{10}{47} times frac{9}{46} = frac{90}{2162} approx frac{1}{24} approx 0.04163 end{matrix} . Other examples of runner-runner draws from a common set of outs are drawing to three or four of a kind. When counting outs, it is convenient to convert runner-runner outs to "normal" outs (see "After the flop "). A runner-runner flush draw is about the equivalent of one "normal" out.
The following table shows the probability and odds of making a runner-runner from a common set of outs and the equivalent normal outs.
Likely drawing to
Common outs
Probability
Odds
Equivalent outs
Four of a kind (with pair) 2
0.00093
1,080 : 1
0.02
Three of a kind (with no pair)
3
0.00278
359 : 1
0.07
4
0.00556
179 : 1
0.13
5
0.00925
107 : 1
0.22
Two pair or three of a kind (with no pair)
6
0.01388
71.1 : 1
0.33
7
0.01943
50.5 : 1
0.46
8
0.02590
37.6 : 1
0.61
9
0.03330
29.0 : 1
0.78
Flush
10
0.04163
23.0 : 1
0.98
Disjoint outs Two outs are disjoint when there are no common cards between the set of cards needed for the first out and the set of cards needed for the second out. The outs are independent of each other if it does not matter which card comes first, and one card appearing does not affect the probability of the other card appearing except by changing the number of remaining cards; an example is drawing two cards to an inside straight. The outs are conditional on each other if the number of outs available for the second card depends on the first card; an example is drawing two cards to an outside straight.
After the flop, if x is the number of independent outs for one card and y is the number of outs for the second card, then the probability P of making the runner-runner is
P = frac{x}{47} times frac{y}{46} times 2 = frac{xy}{1081}. For example, a player holding J♦ Q♦ 9♥ 5♣ 4♠10 and either a K or 8 on the turn and river to make a straight. There are 4 10 s and 8 kings and 8 s, so the probability is begin{matrix}frac{4 times 8}{1081} approx 0.0296end{matrix} .
The probability of making a conditional runner-runner depends on the condition. For example, a player holding 9♥ 10♥ 8♦ 2♠ A♣J , Q }, {7 , J } or {6 , 7 }. The number of outs for the second card is conditional on the first card—a Q or 6 (8 cards) on the first card leaves only 4 outs (J or 7 , respectively) for the second card, while a J or 7 (8 cards) for the first card leaves 8 outs ({Q , 7 } or {J , 6 }, respectively) for the second card. The probability P of a runner-runner straight for this hand is calculated by the equation
P = left(frac{8}{47} times frac{4}{46}right) + left(frac{8}{47} times frac{8}{46}right) = frac{96}{2162} approx 0.0444 The following table shows the probability and odds of making a runner-runner from a disjoint set of outs for common situations and the equivalent normal outs.
Drawing to
Probability
Odds
Equivalent outs
Outside straight
0.04440
21.5 : 1
1.04
Inside+outside straight
0.02960
32.8 : 1
0.70
Inside-only straight
0.01480
66.6 : 1
0.35
Outside straight flush
0.00278
359 : 1
0.07
Inside+outside straight flush
0.00185
540 : 1
0.04
The preceding table assumes the following definitions.Outside straight and straight flush
Drawing to a sequence of three cards of consecutive rank from 3-4-5 to 10-J-Q where two cards can be added to either end of the sequence to make a straight or straight flush.Inside+outside straight and straight flush Drawing to a straight or straight flush where one required rank can be combined with one of two other ranks to make the hand. This includes sequences like 5-7-8 which requires a 6 plus either a 4 or 9 as well as the sequences J-Q-K , which requires a 10 plus either a 9 or A , and 2-3-4 which requires a 5 plus either an A or 6 .Inside-only straight and straight flush Drawing to a straight or straight flush where there are only two ranks that make the hand. This includes hands such as 5-7-9 which requires a 6 and an 8 as well as A-2-3 which requires a 4 and a 5 . Compound outs The strongest runner-runner probabilities lie with hands that are drawing to multiple hands with different runner-runner combinations. These include hands that can make a straight, flush or straight flush, as well as four of a kind or a full house. Calculating these probabilities requires adding the compound probabilities for the various outs, taking care to account for any shared hands. For example, if P_s is the probability of a runner-runner straight, P_f is the probability of a runner-runner flush, and P_{sf} is the probability of a runner-runner straight flush, then the compound probability P of getting one of these hands is
P = P_s + P_f - P_{sf}. The probability of the straight flush is subtracted from the total because it is already included in both the probability of a straight and the probability of a flush, so it has been added twice and must therefore be subtracted from the compound outs of a straight or flush.
The following table gives the compound probability and odds of making a runner-runner for common situations and the equivalent normal outs.
Drawing to
Probability
Odds
Equivalent outs
Flush, outside straight or straight flush
0.08326
11.0 : 1
1.98
Flush, inside+outside straight or straight flush
0.06938
13.4 : 1
1.65
Flush, inside-only straight or straight flush
0.05550
17.0 : 1
1.30
Some hands have even more runner-runner chances to improve. For example, holding the hand J♠ Q♠ after a flop of 10♠ J♥ 7♦ there are several runner-runner hands to make at least a straight. The hand can get two cards from the common outs of {J , Q } (5 cards) to make a full house or four of a kind, can get a J (2 cards) plus either a 7 or 10 (6 cards) to make a full house from these independent disjoint outs, and is drawing to the compound outs of a flush, outside straight or straight flush. The hand can also make {7 , 7 } or {10 , 10 } (each drawing from 3 common outs) to make a full house, although this will make four of a kind for anyone holding the remaining 7 or 10 or a bigger full house for anyone holding an overpair . Working from the probabilities from the previous tables and equations, the probability P of making one of these runner-runner hands is a compound probability
P = 0.08326 + 0.00925 + frac{2 times 6}{1081} + (0.00278 times 2) approx 0.1092 and odds of 8.16 : 1 for the equivalent of 2.59 normal outs. Almost all of these runner-runners give a winning hand against an opponent who had flopped a straight holding 8 , 9 , but only some give a winning hand against A♠ 2♠ (this hand makes bigger flushes when a flush is hit) or against K♣ Q♦ (this hand makes bigger straights when a straight is hit with 8 9 ). When counting outs, it is necessary to adjust for which outs are likely to give a winning hand—this is where the skill in poker becomes more important than being able to calculate the probabilities.
See also Poker topics:
Math and probability topics:
Notes
The odds presented in this article use the notation x : 1 which translates to x to 1 odds against the event happening. The odds are calculated from the probability p p ) ÷ p ] : 1, or odds = [(1 ÷ p ) − 1] : 1. Another way of expressing the odds x : 1 is to state that there is a 1 in x+1 chance of the event occurring or the probability of the event occurring is 1/(x+1). So for example, the odds of a role of a fair six-sided die coming up three is 5 : 1 against because there are 5 chances for a number other than three and 1 chance for a three; alternatively, this could be described as a 1 in 6 chance or begin{matrix}frac{1}{6}end{matrix} probability of a three being rolled because the three is 1 of 6 equally-likely possible outcomes.
^ By removing reflection and applying aggressive search tree pruning , it is possible to reduce the number of unique head-to-head hand combinations from 207,025 to less than 50,000. Reflection eliminates redundant calculations by observing that given hands h_1 and h_2 , if w_1 is the probability of h_1 beating h_2 in a showdown and s is the probability of h_1 splitting the pot with h_2 , then the probability w_2 of h_2 beating h_1 is w_2 = 1 - (s + w_1) , thus eliminating the need to evaluate h_2 against h_1 . Pruning is possible, for example, by observing that Q♥ J♥ 8♦ 7♣8♦ 7♠not the same probability as against 8♥ 7♣
See "Capital Pi notation for multiplication " for a description of the prod (capital π or pi) symbol.
In the example, if the opponent is holding either 8♥ 9♥ 8♦ 9♦ 8♦ 9♦ 10♦ J♦
References
Mike Petriv (1996). Hold'em Odds Book . Objective Observer Press. ISBN 0-9681223-0-2.King Yao (2005). Weighing the Odds in Hold 'em Poker . Pi Yee Press. ISBN 0-935926-25-9.Dan Harrington, Bill Robertie (2005). Harrington on Hold'em Volume 1: Strategic Play . Two Plus Two Publishing. ISBN 1-880685-33-7.
External links
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