The solar luminosity
, is a unit of luminosity
emitted in the form of photons
) conventionally used by astronomers
to give the luminosities of stars
It is equal to the current accepted luminosity of the Sun
, which is 3.839 × 1026 W
, or 3.839 × 1033erg
Note that the Sun is a weak variable star
and its luminosity therefore fluctuates
Calculating with this constant
You can calculate how much solar power hits the Earth by comparing a cross sectional area of the Earth and the total surface area of a sphere with a radius equal to the distance of the earth from the sun.
- The Earth's radius is 3963 miles (6,378 km).
- The Earth's cross sectional area = π×radius2 = 49.3 million square miles (128,000,000 km²).
- The Sun's average distance is about 93 million miles (150,000,000 km).
- The surface area of a sphere = 4×π×radius2 = 1.09×1017 square miles (2.82×1017 km²).
- Power reaching the Earth = P(total) × Area(earth)/Area(sphere) = 1.77×1017 W.
- The power hitting a square meter of area on Earth: (square meter = 1/16092 square miles)
- Power over square meter = P(total)(1/16092)/area(sphere) = 1387 W (the solar constant)
- Estimates have been made that humans use about 12×1012 W.
- How much land area would be needed to power that?
- The best solar cells can produce about 33% efficiency.
- Area needed = 12×1012/(1387×0.33) = 26×109 m2 = 10122 square miles ~100×100 mile square. (More is needed since the sun is not always straight over head, and because some fraction of the radiation does not reach the surface due to clouds and atmospheric scattering.)