Severy, Kansas

Severy is a city in Greenwood County, Kansas, United States. The population was 359 at the 2000 census.


Severy is located at (37.622487, -96.227635).

According to the United States Census Bureau, the city has a total area of 0.5 square miles (1.3 km²), all of it land.


As of the census of 2000, there were 359 people, 152 households, and 89 families residing in the city. The population density was 710.9 people per square mile (277.2/km²). There were 197 housing units at an average density of 390.1/sq mi (152.1/km²). The racial makeup of the city was 96.38% White, 1.95% Native American, 0.28% from other races, and 1.39% from two or more races. Hispanic or Latino of any race were 0.84% of the population.

There were 152 households out of which 28.9% had children under the age of 18 living with them, 48.7% were married couples living together, 7.2% had a female householder with no husband present, and 41.4% were non-families. 33.6% of all households were made up of individuals and 17.8% had someone living alone who was 65 years of age or older. The average household size was 2.36 and the average family size was 3.03.

In the city the population was spread out with 27.3% under the age of 18, 6.4% from 18 to 24, 25.6% from 25 to 44, 21.7% from 45 to 64, and 18.9% who were 65 years of age or older. The median age was 39 years. For every 100 females there were 88.9 males. For every 100 females age 18 and over, there were 86.4 males.

The median income for a household in the city was $23,393, and the median income for a family was $29,583. Males had a median income of $30,208 versus $24,063 for females. The per capita income for the city was $12,623. About 8.1% of families and 12.3% of the population were below the poverty line, including 10.9% of those under age 18 and 3.2% of those age 65 or over.


External links

Search another word or see severyon Dictionary | Thesaurus |Spanish
Copyright © 2015, LLC. All rights reserved.
  • Please Login or Sign Up to use the Recent Searches feature