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In arithmetic, when the result of the division of two integers cannot be expressed with an integer quotient, the remainder is the amount "left over."
## The remainder for natural numbers

If a and d are natural numbers, with d non-zero, it can be proven that there exist unique integers q and r, such that a = qd + r and 0 ≤ r < d. The number q is called the quotient, while r is called the remainder.
The division algorithm provides a proof of this result and also an algorithm describing how to calculate the remainder.
### Examples

## The case of general integers

If a and d are integers, with d non-zero, then a remainder is an integer r such that a = qd + r for some integer q, and with 0 ≤ |r| < |d|.## The remainder for real numbers

When a and d are real numbers, with d non-zero, a can be divided by d without remainder, with the quotient being another real number. If the quotient is constrained to being an integer however, the concept of remainder is still necessary. It can be proved that there exists a unique integer quotient q and a unique real remainder r such that a=qd+r with 0≤r < |d|. As in the case of division of integers, the remainder could be required to be negative, that is, -|d| < r ≤ 0. ## The inequality satisfied by the remainder

The way remainder was defined, in addition to the equality a=qd+r an inequality was also imposed, which was either 0≤ r < |d| or -|d| < r ≤ 0. Such an inequality is necessary in order for the remainder to be unique — that is, for it to be well-defined. The choice of such an inequality is somewhat arbitrary. Any condition of the form x < r ≤ x+|d| (or x ≤ r < x+|d|), where x is a constant, is enough to guarantee the uniqueness of the remainder.
## Quotient and remainder in programming languages

With two choices for the inequality, there are two possible choices for the remainder, one is negative and the other is positive. This means that there are also two possible choices for the quotient. Usually, in number theory, we always choose the positive remainder. But programming languages do not. C99 and Pascal choose the remainder with the same sign as the dividend a. (Before C99, the C language allowed either choice.) Perl and Python choose the remainder with the same sign as the divisor d.
## See also

## References

- When dividing 13 by 10, 1 is the quotient and 3 is the remainder, because 13=1×10+3.
- When dividing 26 by 4, 6 is the quotient and 2 is the remainder, because 26=6×4+2.
- When dividing 56 by 7, 8 is the quotient and 0 is the remainder, because 56=7×8+0.
- When dividing 3 by 10, 3 is the remainder as we always take the front number as the remainder when the second number is of higher value.

When defined this way, there are two possible remainders. For example, the division of −42 by −5 can be expressed as either

- −42 = 9×(−5) + 3

as is usual for mathematicians, or

- −42 = 8×(−5) + (−2).

So the remainder is then either 3 or −2.

This ambiguity in the value of the remainder can be quite serious computationally; for mission critical computing systems, the wrong choice can lead to dangerous consequences. In the case above, the negative remainder is obtained from the positive one just by subtracting 5, which is d. This holds in general. When dividing by d, if the positive remainder is r_{1}, and the negative one is r_{2}, then

- r
_{1}= r_{2}+ d.

Extending the definition of remainder for real numbers as described above is not of theoretical importance in mathematics; however, many programming languages implement this definition — see modulo operation.

- Chinese remainder theorem
- Division algorithm
- Euclidean algorithm
- Modulo
- Modular arithmetic
- Modulo operation

- Davenport, Harold (1999).
*The higher arithmetic: an introduction to the theory of numbers*. Cambridge, UK: Cambridge University Press. - Zuckerman, Martin M
*Arithmetic: A Straightforward Approach*. Lanham, Md: Rowman & Littlefield Publishers, Inc.

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Last updated on Monday October 06, 2008 at 23:49:15 PDT (GMT -0700)

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This article is licensed under the GNU Free Documentation License.

Last updated on Monday October 06, 2008 at 23:49:15 PDT (GMT -0700)

View this article at Wikipedia.org - Edit this article at Wikipedia.org - Donate to the Wikimedia Foundation

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