Added to Favorites

Related Searches

Nearby Words

In mathematics, the greatest common divisor (gcd), sometimes known as the greatest common factor (gcf) or highest common factor (hcf), of two non-zero integers, is the largest positive integer that divides both numbers without remainder. ## Overview

## Calculating the gcd

## Properties

## Probabilities and expected value

## The gcd in commutative rings

## See also

## References

## Further reading

## External links

This notion has been extended to polynomials, see Greatest common divisor of two polynomials.

The greatest common divisor of a and b is written as gcd(a, b), or sometimes simply as (a, b). For example, gcd(12, 18) = 6, gcd(−4, 14) = 2 and gcd(5, 0) = 5. Two numbers are called coprime or relatively prime if their greatest common divisor equals 1. For example, 9 and 28 are relatively prime.

The greatest common divisor is useful for reducing fractions to be in lowest terms. For example, gcd(42, 56)=14, therefore,

- $\{42\; over\; 56\}=\{3\; cdot\; 14\; over\; 4\; cdot\; 14\}=\{3\; over\; 4\}.$

Greatest common divisors can in principle be computed by determining the prime factorizations of the two numbers and comparing factors, as in the following example: to compute gcd(18,84), we find the prime factorizations 18 = 2·3^{2} and 84 = 2^{2}·3·7 and notice that the "overlap" of the two expressions is 2·3; so gcd(18,84) = 6. In practice, this method is only feasible for very small numbers; computing prime factorizations in general takes far too long.

A much more efficient method is the Euclidean algorithm, which uses the division algorithm in combination with the observation that the gcd of two numbers also divides their difference: divide 84 by 18 to get a quotient of 4 and a remainder of 12. Then divide 18 by 12 to get a quotient of 1 and a remainder of 6. Then divide 12 by 6 to get a remainder of 0, which means that 6 is the gcd.

The series of quotients generated by the Euclidean algorithm compose a continued fraction.

If a and b are not both zero, the greatest common divisor of a and b can be computed by using least common multiple (lcm) of a and b:

- $operatorname\{gcd\}(a,b)=frac\{acdot\; b\}\{operatorname\{lcm\}(a,b)\}.$

Keith Slavin has shown that for odd a≥1:

- $operatorname\{gcd\}(a,b)=log\_2prod\_\{k=0\}^\{a-1\}\; (1+e^\{-2ipi\; k\; b/a\})$

which is a function that can be evaluated for complex b. Marcelo Polezzi has shown that:

- $operatorname\{gcd\}(a,b)=2sum\_\{k=1\}^\{a-1\}\; lfloor\; k\; b/arfloor+a+b-a\; b$

for positive integers a and b. Donald Knuth has proved the following reduction:

- $operatorname\{gcd\}(2^a-1,2^b-1)=2^\{gcd(a,b)\}-1$

for non-negative integers a and b, where a and b are not both zero.

- Every common divisor of a and b is a divisor of gcd(a, b).
- gcd(a, b), where a and b are not both zero, may be defined alternatively and equivalently as the smallest positive integer d which can be written in the form d = a·p + b·q where p and q are integers. This expression is called Bézout's identity. Numbers p and q like this can be computed with the extended Euclidean algorithm.
- gcd(a, 0) = |a|, for a ≠ 0, since any number is a divisor of 0, and the greatest divisor of a is |a|. This is usually used as the base case in the Euclidean algorithm.
- If a divides the product b·c, and gcd(a, b) = d, then a/d divides c.
- If m is a non-negative integer, then gcd(m·a, m·b) = m·gcd(a, b).
- If m is any integer, then gcd(a + m·b, b) = gcd(a, b).
- If m is a nonzero common divisor of a and b, then gcd(a/m, b/m) = gcd(a, b)/m.
- The gcd is a multiplicative function in the following sense: if a
_{1}and a_{2}are relatively prime, then gcd(a_{1}·a_{2}, b) = gcd(a_{1}, b)·gcd(a_{2}, b). - The gcd is a commutative function: gcd(a, b) = gcd(b, a).
- The gcd is an associative function: gcd(a, gcd(b, c)) = gcd(gcd(a, b), c).
- The gcd of three numbers can be computed as gcd(a, b, c) = gcd(gcd(a, b), c), or in some different way by applying commutativity and associativity. This can be extended to any number of numbers.
- gcd(a, b) is closely related to the least common multiple lcm(a, b): we have

- gcd(a, b)·lcm(a, b) = a·b.

- This formula is often used to compute least common multiples: one first computes the gcd with Euclid's algorithm and then divides the product of the given numbers by their gcd. The following versions of distributivity hold true:

- gcd(a, lcm(b, c)) = lcm(gcd(a, b), gcd(a, c))

- lcm(a, gcd(b, c)) = gcd(lcm(a, b), lcm(a, c)).

- It is useful to define gcd(0, 0) = 0 and lcm(0, 0) = 0 because then the natural numbers become a complete distributive lattice with gcd as meet and lcm as join operation. This extension of the definition is also compatible with the generalization for commutative rings given below.
- In a Cartesian coordinate system, gcd(a, b) can be interpreted as the number of points with integral coordinates on the straight line joining the points (0, 0) and (a, b), excluding (0, 0).

The probability that two randomly chosen (unlimited) integers $A$ and $B$ have a given greatest common divisor $d$ is $6over\; \{pi^2\; d^2\}$. This follows from the characterization of $gcd(A,B)$ as the integer $d$ such that $d|A,B$ and $A/d$ and $B/d$ are coprime. The probability of two integers sharing a factor $d$ is $d^\{-2\}$. The probability that two integers are coprime is $1/zeta(2)=6/pi^2$. (See coprime for a derivation.)

Using this information, the expected value of the greatest common divisor function can be computed. This is

- $mathrm\{E\}(mathrm\{2\}\; )\; =\; sum\_\{d=1\}^\{infty\}\; d\; frac\{6\}\{pi^2\; d^2\}\; =\; frac\{6\}\{pi^2\}\; sum\_\{d=1\}^\{infty\}\; frac\{1\}\{d\}.$

This last summation is the Harmonic series, which diverges. Hence the expected value of the greatest common divisor of two variables is not well-defined. This is not the case in general, however. For the greatest common divisor of $k\; ge\; 3$ variables, the expected value is well-defined, and by the above argument, it is

- $mathrm\{E\}(k)\; =\; sum\_\{d=1\}^\{infty\}\; d^\{1-k\}\; zeta(k)^\{-1\}\; =\; frac\{zeta(k-1)\}\{zeta(k)\}.$

where $zeta(k)$ is the Riemann zeta function.

For $k=3$, this is approximately equal to 1.3684. For $k=4$, it is approximately 1.1106.

if all integers x are limited as $m\; ge\; x\; ge\; 1$ then the results can be extended to

- $mathrm\{E\}(k,m)\; =\; frac\{sum\_\{d=1\}^\{m\}\; d^\{1-k\}\}\{sum\_\{t=1\}^\{m\}\; t^\{-k\}\}\; =\; frac\{zeta(k-1)-zeta(k-1,m+1)\}\{zeta(k)-zeta(k,m+1)\}.$

where $zeta(k,m)$ is the Hurwitz zeta function.

if different $m$'s are known for different $x$ then the lowest $m$ is taken.

The greatest common divisor can more generally be defined for elements of an arbitrary commutative ring.

If R is a commutative ring, and a and b are in R, then an element d of R is called a common divisor of a and b if it divides both a and b (that is, if there are elements x and y in R such that d·x = a and d·y = b). If d is a common divisor of a and b, and every common divisor of a and b divides d, then d is called a greatest common divisor of a and b.

Note that with this definition, two elements a and b may very well have several greatest common divisors, or none at all. But if R is an integral domain then any two gcd's of a and b must be associate elements. Also, if R is a unique factorization domain, then any two elements have a gcd. If R is a Euclidean domain then a form of the Euclidean algorithm can be used to compute greatest common divisors.

The following is an example of an integral domain with two elements that do not have a gcd:

- $R\; =\; mathbb\{Z\}left[sqrt\{-3\}right],quad\; a\; =\; 4\; =\; 2cdot\; 2\; =\; left(1+sqrt\{-3\}right)left(1-sqrt\{-3\}right),quad\; b\; =\; left(1+sqrt\{-3\}right)cdot\; 2.$

The elements $1+sqrt\{-3\}$ and $2$ are two "maximal common divisors" (i.e. any common divisor which is a multiple of 2 is associated to 2, the same holds for $1+sqrt\{-3\}$), but they are not associated, so there is no greatest common divisor of a and b.

Corresponding to the Bezout property we may, in any commutative ring, consider the collection of elements of the form $p\; a\; +\; q\; b$, where p and q range over the ring. This is the ideal generated by a and b, and is denoted simply $(a,b)$. In a ring all of whose ideals are principal (a principal ideal domain or PID), this ideal will be identical with the set of multiples of some ring element d; then this d is a greatest common divisor of a and b. But the ideal $(a,b)$ can be useful even when there is no greatest common divisor of a and b. (Indeed, Ernst Kummer used this ideal as a replacement for a gcd in his treatment of Fermat's Last Theorem, although he envisioned it as the set of multiples of some hypothetical, or ideal, ring element d, whence the ring-theoretic term.)

- Least common multiple
- Lowest common denominator
- Binary GCD algorithm
- Euclidean algorithm
- Extended Euclidean algorithm
- Greatest common divisor of two polynomials

- Donald Knuth. The Art of Computer Programming, Volume 2: Seminumerical Algorithms, Third Edition. Addison-Wesley, 1997. ISBN 0-201-89684-2. Section 4.5.2: The Greatest Common Divisor, pp.333–356.
- Thomas H. Cormen, Charles E. Leiserson, Ronald L. Rivest, and Clifford Stein. Introduction to Algorithms, Second Edition. MIT Press and McGraw-Hill, 2001. ISBN 0-262-03293-7. Section 31.2: Greatest common divisor, pp.856–862.
- Saunders MacLane and Garrett Birkhoff. A Survey of Modern Algebra, Fourth Edition. MacMillan Publishing Co., 1977. ISBN 0-02-310070-2. 1-7: "The Euclidean Algorithm."

- greatest common divisor at Everything2.com
- Greatest Common Measure: The Last 2500 Years, by Alexander Stepanov
- Online gcd calculator(4 methods)
- Online HCF calculator
- Online gcd calculator

Wikipedia, the free encyclopedia © 2001-2006 Wikipedia contributors (Disclaimer)

This article is licensed under the GNU Free Documentation License.

Last updated on Thursday October 02, 2008 at 21:22:36 PDT (GMT -0700)

View this article at Wikipedia.org - Edit this article at Wikipedia.org - Donate to the Wikimedia Foundation

This article is licensed under the GNU Free Documentation License.

Last updated on Thursday October 02, 2008 at 21:22:36 PDT (GMT -0700)

View this article at Wikipedia.org - Edit this article at Wikipedia.org - Donate to the Wikimedia Foundation

Copyright © 2015 Dictionary.com, LLC. All rights reserved.