A permutation of a set G is any bijective function taking G onto G; and the set of all such functions forms a group under function composition, called the symmetric group on G, and written as Sym(G).
Cayley's theorem puts all groups on the same footing, by considering any group (including infinite groups such as (R,+)) as a permutation group of some underlying set. Thus, theorems which are true for permutation groups are true for groups in general.
Attributed in Burnside to Jordan, Eric Nummela nonetheless argues that the standard name for this theorem -- "Cayley's Theorem" -- is in fact appropriate. Cayley, in his original 1854 paper which introduced the concept of a group, showed that the correspondence in the theorem is one-to-one, but he failed to explicitly show it was a homomorphism (and thus an isomorphism). However, Nummela notes that Cayley made this result known to the mathematical community at the time, thus predating Jordan by 16 years or so.
The subset K of Sym(G) defined as K = {fg : g in G and fg(x) = g*x for all x in G} is a subgroup of Sym(G) which is isomorphic to G. The fastest way to establish this is to consider the function T : G → Sym(G) with T(g) = fg for every g in G. T is a group homomorphism because (using "•" for composition in Sym(G)):(fg • fh)(x) = fg(fh(x)) = fg(h*x) = g*(h*x) = (g*h)*x = f(g*h)(x), for all x in G, and hence: T(g) • T(h) = fg • fh = f(g*h) = T(g*h). The homomorphism T is also injective since T(g) = idG (the identity element of Sym(G)) implies that g*x = x for all x in G, and taking x to be the identity element e of G yields g = g*e = e. Alternatively, T(g) is also injective since, if g*x=g*x' implies x=x' (by pre-multiplying with the inverse of g, which exists because G is a group).
Thus G is isomorphic to the image of T, which is the subgroup K.
T is sometimes called the regular representation of G.
Firstly, suppose with . Then the group action is by classification of G-orbits (also known as the orbit-stabilizer theorem).
Now, the representation is faithful if is injective, that is, if the kernel of is trivial. Suppose ∈ ker Then, by the equivalence of the permutation representation and the group action. But since ∈ ker , and thus ker is trivial. Then im and thus the result follows by use of the first isomorphism theorem.
Z3 = {0,1,2} with addition modulo 3; group element 0 corresponds to the identity permutation e, group element 1 to permutation (123), and group element 2 to permutation (132). E.g. 1 + 1 = 2 corresponds to (123)(123)=(132).
Z4 = {0,1,2,3} with addition modulo 4; the elements correspond to e, (1234), (13)(24), (1432).
The elements of Klein four-group {e, a, b, c} correspond to e, (12)(34), (13)(24), and (14)(23).
S3 (dihedral group of order 6) is the group of all permutations of 3 objects, but also a permutation group of the 6 group elements:
| * | e | a | b | c | d | f | permutation |
|---|---|---|---|---|---|---|---|
| e | e | a | b | c | d | f | e |
| a | a | e | d | f | b | c | (12)(35)(46) |
| b | b | f | e | d | c | a | (13)(26)(45) |
| c | c | d | f | e | a | b | (14)(25)(36) |
| d | d | c | a | b | f | e | (156)(243) |
| f | f | b | c | a | e | d | (165)(234) |