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In photography, angle of view describes the angular extent of a given scene that is imaged by a camera. It parallels, and may be used interchangeably with, the more general visual term field of view.

It is important to distinguish the angle of view from the angle of coverage, which describes the angle of projection by the lens onto the focal plane. For most cameras, it may be assumed that the image circle produced by the lens is large enough to cover the film or sensor completely. If the angle of view exceeds the angle of coverage, however, then vignetting will be present in the resulting photograph. For an example of this, see below.

For lenses projecting rectilinear (non-spatially-distorted) images of distant objects, the effective focal length and the image format dimensions completely define the angle of view. Calculations for lenses producing non-rectilinear images are much more complex and in the end not very useful in most practical applications.

Angle of view may be measured horizontally (from the left to right edge of the frame), vertically (from the top to bottom of the frame), or diagonally (from one corner of the frame to its opposite corner).

For a lens projecting a rectilinear image, the angle of view (α) can be calculated from the chosen dimension (d), and effective focal length (f) as follows:

- $alpha\; =\; 2\; arctan\; frac\; \{d\}\; \{2\; f\}$

$d$ represents the size of the film (or sensor) in the direction measured. For example, for film that is 36 mm wide, $d\; =\; 36$ mm would be used to obtain the horizontal angle of view.

Because this is a trigonometric function, the angle of view does not vary quite linearly with the reciprocal of the focal length. However, except for wide-angle lenses, it is reasonable to approximate $alphaapprox\; frac\{d\}\{f\}$ radians or $frac\{180d\}\{pi\; f\}$ degrees.

The effective focal length is nearly equal to the stated focal length of the lens (F), except in macro photography where the lens-to-object distance is comparable to the focal length. In this case, the magnification factor (m) must be taken into account:

- $f\; =\; F\; cdot\; (1\; +\; m\; )$

(In photography $m$ is usually defined to be positive, despite the inverted image.) For example, with a magnification ratio of 1:2, we find $f\; =\; 1.5\; cdot\; F$ and thus the angle of view is reduced by 33% compared to focusing on a distant object with the same lens.

Angle of view can also be determined using FOV tables or paper or software lens calculators.

Consider a 35 mm camera with a normal lens having a focal length of F=50 mm. The dimensions of the 35 mm image format are 24 mm (vertically) × 36 mm (horizontal), giving a diagonal of about 43.3 mm.

Now the angles of view are:

- horizontally, $alpha\_h\; =\; 2arctan;\; h/2f\; approx$ 39.6°
- vertically, $alpha\_v\; =\; 2arctan;\; v/2f\; approx$ 27.0°
- diagonally, $alpha\_d\; =\; 2arctan;\; d/2f\; approx$ 46.7°

Consider a rectilinear lens in a camera used to photograph an object at a distance $S\_1$, and forming an image that just barely fits in the dimension $d$ of the frame (the film or image sensor). Treat the lens as if it were a pinhole at distance $S\_2$ from the image plane (technically, the center of perspective of a rectilinear lens is at the center of its entrance pupil):

Now $alpha/2$ is the angle between the optical axis of the lens and the ray joining its optical center to the edge of the film. Here $alpha$ is defined to be the angle-of-view, since it is the angle enclosing the largest object whose image can fit on the film. We want to find the relationship between:

- the angle $alpha$

- the "opposite" side of the right triangle, $d/2$ (half the film-format dimension)

- the "adjacent" side, $S\_2$ (distance from the lens to the image plane)

- $tan\; (alpha\; /\; 2\; )\; =\; frac\; \{d/2\}\; \{S\_2\}\; .$

- $alpha\; =\; 2\; arctan\; frac\; \{d\}\; \{2\; S\_2\}$

To project a sharp image of distant objects, $S\_2$ needs to be equal to the focal length $F$, which is attained by setting the lens for infinity focus. Then the angle of view is given by:

- $alpha\; =\; 2\; arctan\; frac\; \{d\}\; \{2\; f\}$ where $f=F$

For macro photography, we cannot neglect the difference between $S\_2$ and $F$ From the thin lens formula,

- $frac\{1\}\{F\}\; =\; frac\{1\}\{S\_1\}\; +\; frac\{1\}\{S\_2\}$.

We substitute for the magnification, $m\; =\; S\_2/S\_1$, and with some algebra find:

- $S\_2\; =\; Fcdot(1+m)$

Defining $f=S\_2$ as the "effective focal length", we get the formula presented above:

- $alpha\; =\; 2\; arctan\; frac\; \{d\}\; \{2\; f\}$ where $f=Fcdot(1+m)$.

Lenses are often referred to by terms that express their angle of view:

- Ultra wide-angle lenses, also known as fisheye lenses, cover up to 180° (or even wider in special cases)
- Wide-angle lenses generally cover between 100° and 60°
- Normal, or Standard lenses generally cover between 50° and 25°
- Telephoto lenses generally cover between 15° and 10°
- Super Telephoto lenses generally cover between 8° through less than 1°

Zoom lenses are a special case wherein the focal length, and hence angle of view, of the lens can be altered mechanically without removing the lens from the camera.

Longer lenses magnify the subject more, apparently compressing distance and (when focused on the foreground) blurring the background because of their shallower depth of field. Wider lenses tend to magnify distance between objects while allowing greater depth of field.

Another result of using a wide angle lens is a greater apparent perspective distortion when the camera is not aligned perpendicularly to the subject: parallel lines converge at the same rate as with a normal lens, but converge more due to the wider total field. For example, buildings appear to be falling backwards much more severely when the camera is pointed upward from ground level than they would if photographed with a normal lens at the same distance from the subject, because more of the subject building is visible in the wide-angle shot.

Because different lenses generally require a different camera–subject distance to preserve the size of a subject, changing the angle of view can indirectly distort perspective, changing the apparent relative size of the subject and foreground.

A circular fisheye lens (as opposed to a full-frame fisheye) is an example of a lens where the angle of coverage is less than the angle of view. The image projected onto the film is circular because the diameter of the image projected is narrower than that needed to cover the widest portion of the film.

Focal Length (mm) | 13 | 15 | 18 | 21 | 24 | 28 | 35 | 50 | 85 | 105 | 135 | 180 | 210 | 300 | 400 | 500 | 600 | 830 | 1200 |
---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|

Diagonal (°) | 118 | 111 | 100 | 91.7 | 84.1 | 75.4 | 63.4 | 46.8 | 28.6 | 23.3 | 18.2 | 13.7 | 11.8 | 8.25 | 6.19 | 4.96 | 4.13 | 2.99 | 2.07 |

Vertical (°) | 85.4 | 77.3 | 67.4 | 59.5 | 53.1 | 46.4 | 37.8 | 27.0 | 16.1 | 13.0 | 10.2 | 7.63 | 6.54 | 4.58 | 3.44 | 2.75 | 2.29 | 1.66 | 1.15 |

Horizontal (°) | 108 | 100.4 | 90.0 | 81.2 | 73.7 | 65.5 | 54.4 | 39.6 | 23.9 | 19.5 | 15.2 | 11.4 | 9.80 | 6.87 | 5.15 | 4.12 | 3.44 | 2.48 | 1.72 |

Displaying 3d graphics requires 3d projection of the models onto a 2d surface, and uses a series of mathematical calculations to render the scene. The angle of view of the scene is thus readily set and changed; some renderers even measure the angle of view as the focal length of an imaginary lens. The angle of view can also be projected onto the surface at an angle greater than 90°, effectively creating a fish eye lens effect.

Modifying the angle of view over time, or zooming, is a frequently used cinematic technique.

As an effect, some first person games, especially racing games, widen the angle of view beyond 90° to exaggerate the distance the player is travelling, thus exaggerating the player's perceived speed. This effect can be done progressively, or upon the activation of some sort of "turbo boost." An interesting visual effect in itself, it also provides a way for game developers to suggest speeds faster than the game engine or computer hardware is capable of displaying. Some examples include Burnout Paradise and Grand Theft Auto IV.

Players of first-person shooter games sometimes set the angle of view of the game, widening it in an unnatural way (a difference of 20 or 30 degrees from normal), in order to see more peripherally.

- Angle of View comparison photographs
- Angle of View on digital SLR cameras with reduced sensor size
- Focal Length and Angle of View

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Last updated on Saturday October 11, 2008 at 17:41:09 PDT (GMT -0700)

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This article is licensed under the GNU Free Documentation License.

Last updated on Saturday October 11, 2008 at 17:41:09 PDT (GMT -0700)

View this article at Wikipedia.org - Edit this article at Wikipedia.org - Donate to the Wikimedia Foundation

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