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Vector resolute&o=10616

Vector resolute

The vector resolute (also known as the vector projection) of two vectors, mathbf{a} in the direction of mathbf{b} (also "mathbf{a} on mathbf{b}"), is given by:

(mathbf{a}cdotmathbf{hat b})mathbf{hat b} or (|mathbf{a}|costheta)mathbf{hat b}

where theta is the angle between the vectors mathbf{b} and mathbf{a} and hat{mathbf{b}} is the unit vector in the direction of mathbf{b}.

The vector resolute is a vector, and is the orthogonal projection of the vector mathbf{a} onto the vector mathbf{b}. The vector resolute is also said to be a component of vector mathbf{a} in the direction of vector mathbf{b}.

The other component of mathbf{a} (perpendicular to mathbf{b}) is given by:

mathbf{a} - (mathbf{a}cdotmathbf{hat b})mathbf{hat b}

The vector resolute is also the scalar resolute multiplied by mathbf{hat b} (in order to convert it into a vector, or give it direction).

Vector resolute overview

If A and B are two vectors, the projection (C) of A on B is the vector that has the same slope as B with the length:

|C| = |A| cos theta

To calculate C use the definition of the dot product: A cdot B = |A| , |B| cos theta ,

Using the above equation:

|C| = |A| cos theta

Multiply and divide by |B| at the same time:

|C| = frac

In the resulting fraction, the top term is the same as the dot product, hence:

|C| = frac {A cdot B}

To find the length of |C| with an unknown theta, and unknown direction, multiply it with the unit vector B:

C = frac {A cdot B}

> = frac {A cdot B} {|B|^2} B

Giving the final formula: C = frac {A cdot B} {|B|^2} B

Uses

The vector projection is an important operation in the Gram-Schmidt orthonormalization of vector space bases.

See also

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