Delaware is a town in Nowata County, Oklahoma, United States. The population was 456 at the 2000 census.

Geography

Delaware is located at (36.778150, -95.641785).

According to the United States Census Bureau, the town has a total area of 0.4 square miles (1.0 km²), all of it land.

Demographics

As of the census of 2000, there were 456 people, 171 households, and 129 families residing in the town. The population density was 1,209.6 people per square mile (463.3/km²). There were 194 housing units at an average density of 514.6/sq mi (197.1/km²). The racial makeup of the town was 73.25% White, 21.93% Native American, 0.44% from other races, and 4.39% from two or more races. Hispanic or Latino of any race were 0.66% of the population.

There were 171 households out of which 36.8% had children under the age of 18 living with them, 60.2% were married couples living together, 9.9% had a female householder with no husband present, and 24.0% were non-families. 20.5% of all households were made up of individuals and 9.9% had someone living alone who was 65 years of age or older. The average household size was 2.67 and the average family size was 3.05.

In the town the population was spread out with 28.1% under the age of 18, 11.0% from 18 to 24, 27.9% from 25 to 44, 20.6% from 45 to 64, and 12.5% who were 65 years of age or older. The median age was 36 years. For every 100 females there were 109.2 males. For every 100 females age 18 and over, there were 97.6 males.

The median income for a household in the town was $28,167, and the median income for a family was $31,071. Males had a median income of $27,917 versus $18,125 for females. The per capita income for the town was $11,099. About 9.7% of families and 18.5% of the population were below the poverty line, including 20.7% of those under age 18 and 22.7% of those age 65 or over.

References

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